Answer: 4004ways
Step-by-step explanation:
Total number of Students =15
Total number of students to be on the committee =5
Since two members are of the same major and must not be on the committee, then we are left with choosing 5 people from just 14 People after we eventually remove one from those two students with same majors.
Hence to select 5 people from 14 people, we use the combination formula 14C5.
From the two students with same major we also use the combination Formula in knowing the number of ways any of the two students can be chosen. To choose one from these two students, we use the combination Formula 2C1.
Hence, the total number of ways to choose the committee of 5 and ensuring the two students with same major aren't on the committee becomes:
= 14C5 * 2C1
= 2002 * 2
= 4004ways.
The answer is 2.9. You would round up since there is a 5
0.003 is 1/10 of 0.03.
Just multiply the 0.003 by 10 and you'll get the result. The easiest way to multiply such numbers is to move the dot one position to the right (it would be 2 positions if multiplying by 100, 3 by 1000 etc.). You can do the same with dividing, just remember to move to the left then.
Answer: Toby will pay $34.45.
Step-by-step explanation:
I did 60% of 52 and the 6.25% of 52 and added my answers together.
