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STALIN [3.7K]
3 years ago
7

A man has 3 different suits, 4 different shirts and 5 different pairs of shoes. In how many different ways can this man wear a s

uit, a shirt and a pair of shoes? 35 12 60 17
Mathematics
2 answers:
Shkiper50 [21]3 years ago
8 0

Answer:

60 ways

Step-by-step explanation:

Multiply the number of suits, shirts and shoes to find the number of ways

3 * 4 * 5

60 ways

AleksandrR [38]3 years ago
8 0

Answer:

60

Step-by-step explanation:

(4 x 3) 5

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What is the solution to this inequality?
solong [7]

Answer: x>−4

Step-by-step explanation:

Let's solve your inequality step-by-step.

6x−5>−29

Step 1: Add 5 to both sides.

6x−5+5>−29+5

6x>−24

Step 2: Divide both sides by 6.

6x/6>-24/6

<h3>x>-4</h3>
7 0
3 years ago
Please help!<br><br> which multiplication expression is equivalent to
jenyasd209 [6]

the answer is C................................

5 0
3 years ago
Katie wants to collect over 100 seashells. She already has 34 seashells in her collection. Each day, she finds 12 more seashells
dlinn [17]

Answer:

12d+34>100  

Step-by-step explanation:

Let d be the number of days.

We have been that each day Katie finds 12 more seashells on beach, so after collecting shells for d days Katie will have 12d shells.  

We are also told that Katie already has 34 seashells in her collection, so total number of shells in Katie collection after d days will be: 12d+34

As Katie wants to collect over 100 seashells, so the total number of shells collected in d days will be greater than 100. We can represent this information in an inequality as:

12d+34>100

Therefore, the inequality 12d+34>100 can be used to find the number of days, d, it will take Katie to collect over 100 seashells.

8 0
3 years ago
Read 2 more answers
Let f be the function given by f(x)= (x-1)(x^2-4)/x^2-a. For what positive values of a is f continuous for all real numbers x?
9966 [12]

Answer:

a =1 and a=4.

Step-by-step explanation:

The function is

f(x)=\frac{(x-1)(x^2-4)}{x^2-a}

If we want f(x) to be continuous the denominator needs to be different to 0, otherwise f(x) will be indeterminate.

Now, for a a positive real we have that x=\sqrt{a} will annulate the denominator, i.e

(\sqrt{a})^2-a = a-a = 0. But, if a = 1 we have:

f(x)=\frac{(x-1)(x^2-4)}{x^2-1} = \frac{(x-1)(x^2-4)}{(x-1)(x+1)}=\frac{(x^2-4)}{x+1}

so, the value x=\sqrt{a} = \sqrt{1} = 1 won't annulate the denominator.

Now, for a = 4 we have:

f(x)=\frac{(x-1)(x^2-4)}{x^2-4} = x-1

so, the value x=\sqrt{a} = \sqrt{4} = 2 won't annulate the denominator.

In conclusion, for a=1 or a=1, the function will be continuos for all real numbers, since the denominator will never be 0.

4 0
3 years ago
Let fx) = 8x-3<br> What is (5)?<br> O A. 40<br> O B. 37<br> O C. 45<br> O D. 43
saveliy_v [14]

Answer:

I'm not sure i think B. 37

Step-by-step explanation:

f(x) = 8x-3

f(5)= 8(5)-3

40-3=37

8 0
3 years ago
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