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wolverine [178]
3 years ago
8

An object has rotational inertia I. The object, initially at rest, begins to rotate with a constant angular acceleration of magn

itude α. What is the magnitude of the angular momentum L of the object after time t? Express your answer in terms of I, α, and t.
Physics
1 answer:
butalik [34]3 years ago
3 0

Answer:

Explanation:

initial angular velocity, ωo = 0

angular acceleration = α

time = t

let the angular velocity after time t is ω.

Use first equation of motion for rotational motion

ω = o + α t

ω = αt

The angular momentum is given by

Angular momentum = moment of inertia x angular velocity

L = I x ω

L = I x αt

L = I α t

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A skull believed to belong to an ancient human being has a carbon-14 decay rate of 5.4 disintegrations per minute per gram of ca
larisa86 [58]

Answer:

9.43*10^3 year

Explanation:

For this question, we ought to remember, or know that the half life of carbon 14 is 5730, and that would be vital in completing the calculation

To start with, we use the formula

t(half) = In 2/k,

if we make k the subject of formula, we have

k = in 2/t(half), now we substitute for the values

k = in 2 / 5730

k = 1.21*10^-4 yr^-1

In(A/A•) = -kt, on rearranging, we find out that

t = -1/k * In(A/A•)

The next step is to substitite the values for each into the equation, giving us

t = -1/1.21*10^-4 * In(5.4/15.3)

t = -1/1.21*10^-4 * -1.1041

t = 0.943*10^4 year

8 0
4 years ago
A cannon is rigidly attached to a carriage, which can move along horizontal rails but is connected to a post by a large spring,
Mademuasel [1]

Answer:

Explanation:

Given

mass of cannon and cart is m_1=6475.91 kg

Spring constant k=20000 N/m

mass of Projectile m_2=234 kg

Launch Velocity of cannon v_2=170 m/s

Launch angle \theta =31.3^{\circ}

As the External Force is zero therefore we can conserve momentum

Initially both Projectile and cannon is at rest

Conserving momentum in horizontal direction

m_1u_1+m_2u_2=m_1v_1+m_2v_2\cos 31.3

0+0=6475.91\times v_1+234\times 170\cdot \cos (31.3)

v_1=-\frac{234\times 170\cdot \cos (31.3)}{6475.91}

v_1=-5.24 m/s

i.e. cannon is moving in opposite direction of Projectile

6 0
4 years ago
an object is placed in front of a curved mirror as shown. which of the labeled positions is the current position of the image
alexandr402 [8]

Answer:A

Explanation:

The image is formed behind the mirror.

4 0
3 years ago
Read 2 more answers
Two identical capacitors are connected parallel. Initially they are charged to a potential V0 and each acquired a charge Q0. The
MrRa [10]

Answer:

Explanation:

capacitance of each capacitor

C₀= Q₀ / V₀

V₀ = Q₀ / C₀

New total capacitance = C₀ ( 1 + K )

Common potential

= total charge / total capacitance

= 2 Q₀ / [ C₀ ( 1 + K ) ]

2 V₀ / ( 1 + K )

b )

Common potential = 2 x V₀ / ( 1 + 7.8 )

= .227  V₀

charge on capacitor with dielectric

= .227  V₀ x 7.8 C₀

= 1.77 V₀C₀

= 1.77 Q₀

Ratio required = 1.77

6 0
3 years ago
Which of the following is NOT a step in the operation of a Geiger counter?
ololo11 [35]
The best and most correct answer among the choices provided by your question is the fourth choice or letter D.

Electric current being detected and measured is not a process <span>in the operation of a Geiger counter.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
5 0
3 years ago
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