Answer:

Explanation:
Given that,
The car traveled a total of 1,200 meters during this test.
We need to find the average speed of the car. The average speed of the car is given by total distance covered divided by the time taken. So,

But putting the value of t we can find the average speed of the car.
Answer:


Explanation:
<u>Spring Potential Energy
</u>
For any expression of the restoring force F as a function of the displacement from the equilibrium point x, the change of potential energy is equivalent to the work done to move the object from one point to another.
(a) The potential energy is

We have that

Thus



(b) Knowing that x=26.5 cm = 0.265 m


I think c yeah sounds right
Answer:
travel time is 32.4 s
maximum speed is 45.36 m/s
Explanation:
given data
distance = 980 m
acceleration = 4.20 m/s² for first 1/4 of that distance
acceleration = -1.40 m/s² for next 3/4 of that distance
to find out
travel time through the 980 m and maximum speed
solution
we know for first 1/4 of that distance is =
= 245 m
so equation of motion
s = ut + 0.5 ×at² .............1
here u is initial speed = 0 and a is acceleration an t is time
s = ut + 0.5 ×at²
245 = 0+ 0.5 ×4.20 (t)²
t = 10.80 s
so
maximum speed at 1/4 of that distance
use equation of motion
v² - u² = 2as
put here value
v² - 0 = 2(4.20)× (245)
v = 45.36 m/s
so maximum speed is 45.36 m/s
and
for 3/4 distance
use equation of motion
v = u + at
here u is here 45.36 and a is acceleration and t is time and v final speed is 0
0 = 45.36 + (-1.40) × t
t = 32.4 s
so travel time is 32.4 s