If the mass of a material is 45 grams and the volume of the material is 11 cm^3, what would the density of the material be?
2 answers:
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a) 22.5 m/s
The initial vertical velocity is given by:
where
u = 35 m/s is the initial speed
is the angle of projection of the ball
Substituting into the equation, we find
b) 26.8 m/s
The initial horizontal velocity is given by:
where
u = 35 m/s is the initial speed
is the angle of projection of the ball
Substituting into the equation, we find
c) 2.30 s
The time it takes for the ball to reach the maximum heigth can be found by considering the vertical motion only. This is a uniformly accelerated motion (free-fall), so we can use the suvat equation
where
is the vertical velocity at time t
is the acceleration of gravity (negative because it is downward)
At the maximum height, the vertical velocity becomes zero, ; substituting, we find the time t at which this happens:
d) 25.8 m
The maximum height can also be found by considering the vertical motion only. We can use the following suvat equation:
where
s is the vertical displacement at time t
Substituting t = 2.30 s, we find the displacement at maximum height, so the maximum height:
e) 123.3 m
In order to find how far does the ball lands, we have to consider the horizontal motion.
First of all, the time it takes for the ball to go back to the ground is twice the time needed for reaching the maximum height:
Then, we consider the horizontal motion. There is no acceleration along this direction, so the horizontal velocity is constant:
Therefore, the horizontal distance travelled during the whole motion is
So, the ball lands 123.3 m far from the initial point.
Answer:
cost of running the furnace during January is $5619.62
Explanation:
given data
runs a day = 13 hours
January days = 31 days
resistance = 7.2 ohm
current = 16.7 A
cost of electricity = $0.10/kWh
to find out
cost of running the furnace during January
solution
first we get her power consumed by furnace that is
Power consumed = ........1
put here value we get
Power consumed =
Power consumed = 38.7347 W
and
Power consumed by furnace in one hour is
Power consumed by furnace in one hour is = Power consumed × 3600
Power consumed by furnace in one hour is = 38.7347 × 3600
Power consumed by furnace in one hour is 139.445kWh
and
Power consumed by furnace in the month of January is
Power consumed by furnace in the month of January = 139.445kWh × 13 hours × 31 days
Power consumed by furnace in the month of January = 56196.335 kWh
so
cost of running the furnace during January is = $0.10/kWh × 56196.335 kWh
cost of running the furnace during January is $5619.62