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Alinara [238K]
3 years ago
13

If the mass of a material is 45 grams and the volume of the material is 11 cm^3, what would the density of the material be?

Physics
2 answers:
Jobisdone [24]3 years ago
5 0
D=m^v
d=45g^11cm^3
D=4.1g/cm^3
Stella [2.4K]3 years ago
3 0

The density of the material would be 4.1 g/cm³.

Density is calculated by dividing the mass by the volume.

D=m÷v

D=45 g÷11 cm³

D=4.1 g/cm³

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Which is a characteristic of an amorphous solid?
12345 [234]

Answer:

4. Becomes softer as temperature rises

Explanation:

An amorphous solid is any noncrystalline solid in which the atoms and molecules are not organized in a definite lattice pattern. Such solids include glass, plastic, and gel. Solids and liquids are both forms of condensed matter; both are composed of atoms in close proximity to each other.

5 0
2 years ago
A wheel rotating about a fixed axis has a constant angular acceleration of 4.0 rad/s2. In a 4.0-s interval the wheel turns throu
Nady [450]

Answer:

The  time interval is  t =  3 \ s

Explanation:

From the question we are told that

    The angular acceleration is  \alpha  =  4.0 \ rad/s^2

     The  time taken is  t  =  4.0 \ s

      The angular displacement is  \theta  = 80 \ radians

     

The angular displacement can be represented by the second equation of motion as shown below

          \theta =  w_i t  +  \frac{1}{2} \alpha t^2

where  w_i is the initial velocity at the start of the 4 second interval

So substituting values

        80 =  w_i *  4 + 0.5 *  4.0 *  (4^2)

=>    w_i  =  12 \ rad/s

Now considering this motion starting from the start point (that is rest ) we have

       w__{4.0 }} =  w__{0}} +  \alpha  * t

Where  w__{0}} is the angular velocity at rest which is zero  and  w__{4}} is the angular velocity after 4.0 second which is calculated as 12 rad/s s

        12 =  0  + 4 t

=>       t =  3 \ s

4 0
2 years ago
Two wooden crates rest on top of one another. The smaller top crate has a mass of m1 = 21 kg and the larger bottom crate has a m
Andrews [41]

Answer:

2.35 m/s²

Explanation:

Given that

Mass of the smaller crate, m₁ = 21 kg

Mass of the larger crate, m₂ = 90 kg

Tensión of the rope, T = 261 N

We know that the sum of all forces for the two objects with a force of friction F and a tension T are:

(i) m₁a₁ = F

(ii) m₂a₂ = T - F, where m and a are the masses and accelerations respectively.

1) no sliding can also mean that:

a₁ = a₂ = a

This makes us merge the two equations written above together as:

m₂a = T - m₁a

If we then solve for a, we would have something like this

a = T / (m₁+m₂)

a = 261 / (21 + 90)

a = 261 / 111

a = 2.35 m/s²

Therefore, the needed acceleration of the small crate is 2.35 m/s²

8 0
3 years ago
PLS ANSWER FAST WILL GIVE BRAINLEST!!!!
amid [387]

Answer:

F = 500 N

Explanation:

F = m × a

F = 1,000 × 0.5

F = 500 kg m/s²

F = 500 N

7 0
3 years ago
How much force is needed to stop a 4000 kg truck moving at 8 m/s in 0 2 seconds?​
maksim [4K]

Answer:

32000 N

Explanation:

Force Calculater

8 0
2 years ago
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