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dmitriy555 [2]
2 years ago
10

A 0.150 kg mass is attached to a spring with k = 18.9 N/m. At the equilibrium position, it moves 2.39 m/s. How much mechanical e

nergy does it have? (Unit = J)​
Physics
1 answer:
Nastasia [14]2 years ago
5 0

Answer:0.428

Explanation: got it right on Acellus

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When a generator rotates a coil of wire in a magnetic field, which of the following is produced?
Sloan [31]
The correct answer is an ''electric current''.
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3 years ago
One kg of air is contained in a piston-cylinder system and it undergoes a Carnot cycle having an efficiency of 60%.The heat tran
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Answer is in the file below

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4 0
2 years ago
A 100 kg bag of sand has a weight on 100 N. When dropped its acceleration is what?
Anettt [7]

Answer:

The acceleration of the bag of sand is 1\ m/s^2.

Explanation:

We have,

Mass of a bag of sand is 100 kg

Weight of the bag of sand is 100 N

It is required to find the acceleration of the bag when it is dropped. The weight of an object is given by :

F =ma

When it is dropped, a = g

g=\dfrac{F}{m}\\\\g=\dfrac{100}{100}\\\\g=1\ m/s^2

So, the acceleration of the bag of sand is 1\ m/s^2.

4 0
3 years ago
Water that flows from behind a large dam can cause machines to produce electricity. What change takes place?
lyudmila [28]
The mechanical energy in the falling water is used to spin the generator, and gets transformed into electrical energy.  That's the first choice on the list.
8 0
3 years ago
Potassium is a crucial element for the healthy operation of the human body. Potassium occurs naturally in our environment and th
Mariulka [41]

Answer:

a) 0.0288 grams

b) 2.6*10^{-10} J/kg

Explanation:

Given that:

A typical human  body contains about 3.0 grams of Potassium per kilogram of body mass

The abundance  for the three isotopes are:

Potassium-39, Potassium-40, and Potassium-41 with abundances are 93.26%, 0.012% and 6.728% respectively.

a)

Thus; a person with a mass of 80 kg will posses = 80 × 3 = 240 grams of potassium.

However, the amount of potassium that is present in such person is :

0.012% × 240 grams

= 0.012/100 × 240 grams

= 0.0288 grams

b)

the effective dose (in Sieverts) per year due to Potassium-40 in an 80- kg body is calculate as follows:

First the Dose in (Gy) = \frac{energy \ absorbed }{mass \ of \ the \ body}

= \frac{1.10*10^6*1.6*10^{-14}}{80}

= 2.2*10^{-10} \ J/kg

Effective dose (Sv) = RBE × Dose in Gy

Effective dose (Sv) =  1.2  *2.2*10^{-10} \ J/kg

Effective dose (Sv) = 2.6*10^{-10} J/kg

 

5 0
3 years ago
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