Probability of survival of one disk, p=1-0.05=0.95
If there are n drives, and failures are independent (e.g. mechanical wear and tear, and not a lightning strike or a current spike), then
Probability of survival = p^n
(a) for two disks, P(2) = 0.95^2=0.9025
(b)for three disks P(3) = 0.95^3 = 0.8574
Work shown above! Answer to both is A
Answer:
473
Step-by-step explanation:
The square surface area is 121 (11x11)
For the triangles, you do 16x11, which equals 176 and then divide by 2, to get 88. Since there are 4 triangles, I did 88x4 and got 352 and then added 121 to get 473
Answer: it will take 18.2 years
Step-by-step explanation:
We would apply the formula,
y = ab^t
Where
a represents the initial amount of bacteria.
t represents the doubling.
From the information given
a = 10
t = 1 hour
Since after 1 hour, the amount of bacteria multiplies by 2, then
y = 2 × 10 = 20
Therefore
20 = 10 × b^1
Dividing through by 10, it becomes
2 = b
The equation becomes
y = 10(2)^t
For 3,000,000 bacteria, then
3000000 = 10(2)^t
3000000/10 = (2)^t
300000 = (2)^t
Taking log of both sides, it becomes
Log 300000 = tlog2
5.477 = 0.301t
t = 5.477/0.301
t = 18.2 years
