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dedylja [7]
1 year ago
12

Plsss help and explain how to do it because im confused​

Mathematics
1 answer:
Ray Of Light [21]1 year ago
7 0
I think this is asking what power when the first number given is raised to it will equal the number within the parentheses. So, for example, the answer to the first question would be 5 because 2^5 = 32. 10^3 = 1000, so the answer is 3, and so on.
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The combined average weight of an okapi and a llama is 450450 kilograms. The average weight of 33 llamas is 190190 kilograms mor
Nataliya [291]

Answer:

Okapi 290 kg

Llama 160 kg


Step-by-step explanation:

Let weight of each llama be  l

Let weight of each okapi be  o


<em>Given, combined weight of 1 okapi and 1 llama is 450, we can write:</em>

<em>l+o=450</em>

<em>Also, average weight of 3 llama is 190 more than the average weight of 1 okapi, thus we can write:</em>

<em>3l-190=o</em>


Now, substituting 2nd equation into 1st equation, we can solve for weight of 1 llama:

l+o=450\\l+(3l-190)=450\\l+3l-190=450\\4l=450+190\\4l=640\\l=\frac{640}{4}=160


Each llama weights 160 kg, now using this and plugging into 2nd equation, we get weight of 1 okapi to be:

o=3l-190\\o=3(160)-190\\o=290

Each okapi weigh 290 kg

5 0
3 years ago
Ethan rollerbladed a total of 623 \text{ km}623 km623, start text, space, k, m, end text over ddd days. He rollerbladed the same
Sever21 [200]

Answer:

Ethan rollerbladed each day  \frac{623}{d}  kilometers.

Step-by-step explanation:

Given:

Ethan rollerbladed a total of 623 km over d days.

Now, to find the kilometers Ethan rollerblade each day.

Total number of distance rollerbladed = 623 km.

Total number of days = d.

<u><em>As, Ethan rollerbladed each day the same distance.</em></u>

Now, to get the distance Ethan rollerbladed in each day we divide total number of distance rollerbladed by total number of days:

Ethan\ rollerbladed\ each\ day\ =\ \frac{Total\ number\ of\ distance\ rollerbladed}{Total\ number\ of\ days}

Ethan\ rollerbladed\ each\ day\ =\ \frac{623}{d}

Therefore, Ethan rollerbladed each day \frac{623}{d}  kilometers.

5 0
3 years ago
Let X denote the temperature (degree C) and let Y denote thetime in minutes that it takes for the diesel engine on anautomobile
BlackZzzverrR [31]

Answer:

Step-by-step explanation:

Given f_{XY} (x,y) = c(4x + 2y +1) ; 0 < x < 40\,and\, 0 < y

a)

we know that \int\limits^\infty_{-\infty}\int\limits^\infty_{-\infty} {f(x,y)} \, dxdy=1

therefore \int\limits^{40}_{-0}\int\limits^2_{0} {c(4x+2y+1)} \, dxdy=1

on integrating we get

c=(1/6640)

b)

P(X>20, Y>=1)=\int\limits^{40}_{20}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy

on doing the integration we get

                        =0.37349

c)

marginal density of X is

f(x)=\int\limits^2_{0} {\frca{1}{6640}(4x+2y+1)} \, dy

on doing integration we get

f(x)=(4x+3)/3320 ; 0<x<40

marginal density of Y is

f(y)=\int\limits^{40}_{0} {\frca{1}{6640}(4x+2y+1)} \, dx

on doing integration we get

f(y)=\frac{(y+40.5)}{83}

d)

P(01)=\int\limits^{40}_{0}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy

solve the above integration we get the answer

e)

P(X>20, 0

solve the above integration we get the answer

f)

Two variables are said to be independent if there jointprobability density function is equal to the product of theirmarginal density functions.

we know f(x,y)

In the (c) bit we got f(x) and f(y)

f(x,y)cramster-equation-2006112927536330036287f(x).f(y)

therefore X and Y are not independent

4 0
3 years ago
Please Help me idk this
oksian1 [2.3K]

Answer:

4/7

Step-by-step explanation:

8 0
3 years ago
a 25-foot wire is to be cut so that the longer piece is one foot longer than 5 times the shorter peice . find the length of each
Wittaler [7]

short piece = x

 long piece = 5x +1

x +5x +1 = 25

6x = 24

x = 24/6 = 4

 short piece = 4 feet

long piece = 21 feet

3 0
3 years ago
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