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3 years ago

How do you solve linear equations (short definition)

Mathematics

1 answer:

Ede4ka [16]3 years ago

6 0

Answer:

by moving x's onto one side and the constants to the other

Step-by-step explanation:

hope that helps

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B = 10 feet area = 35 feet 2 Find the height of the triangle.

Alexandra [31]

Answer:

Height is 7m

Step-by-step explanation:

B = 10 feet area = 35 feet 2 Find the height of the triangle.

Area of triangle = 1/2 b×h

35 = 1/2(10×h)

35 × 2 = 10h

70 = 10h

h = 70/10

h = 7m

8 0

4 years ago

A watch company is developing packaging for its new watch. The designer uses octagons with a base area of 30 in2 and rectangles

bezimeni [28]

Answer:

It's (C) 240in3

Step-by-step explanation:

Volume of the prototype is 250 in.³

5 0

4 years ago

Read 2 more answers

What is the perimeter of a rectangle with sides 2/3x+10 and 1/3x+5

gogolik [260]

Answer:

The perimeter of the rectangle is 2x+ 30

Step-by-step explanation:

Sides of the rectangle are 2/3x+10 and 1/3x+5

Now, Perimeter of the Rectangle = 2(Length + Breadth)

Here, sum of the sides = $(\frac{2}{3}x + 10 ) + (\frac{1}{3}x + 5 ) = (\frac{2}{3}x +\frac{1}{3}x ) + ( 10+ 5 )$

adding like terms with like terms, we get

( $\frac{2x + x}{3}) + 15 = \frac{3x}{3} + 15$

Hence, Sum = (x + 15)

Now, 2(Length + Breadth) = 2(x+15) = 2x + 30

hence, the perimeter of the rectangle = 2x+ 30

8 0

3 years ago

10 points thanks to those who help

nignag [31]

A) a 45 degree angle

3 0

3 years ago

In the problem below, AB, CD, and EF are two-digit numbers, where A, B, C, D, E and F represent distinct digits from 1 to 9. Is

Oksi-84 [34.3K]

Answer:

<em>When both the conditions hold true, F is prime.</em>

Step-by-step explanation:

AB, CD, and EF are two-digit numbers, where A, B, C, D, E and F represent distinct digits from 1 to 9.

+ CD

--------

1st condition, B and D are consecutive.

Adding B and D gives us F.

Possible values can be (F being the unit value after adding not considering the carry over):

B + D = F

1+2=3

2+3=5

3+4=7

4+5=9

5+6=1

6+7=3

7+8=5

8+9=7

Here F is not prime (because 9 is not prime).

Now, let us consider the 2nd condition as well.

i.e. C = 8

For the following

+ CD

--------

C is 8 then A must be 1 because any value other than 1 for A will make the sum of A and C greater than 9 and there will be a carry which is not the case here.

So, E = 8 + 1 = 9

Now, B and D are consecutive and can not be 1, 8 or 9.

So, possible values are:

B + D = F

2 + 3 = 5

3 + 4 = 7

Here F is prime.

So, when both the conditions hold true, F is prime.

3 0

3 years ago