ONE EASY FRESHMEN MATH QUESTION!!
1 answer:
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Answer:
The given function symmetric about the y-axis.
Step-by-step explanation:
The given function is
.... (1)
1. Symmetry about the x-axis: If the point (r, θ ) lies on the graph, then the point (r,-θ ) or (-r, π - θ ) also lies on the graph.
2. Symmetry about the y-axis: If the point (r, θ ) lies on the graph, then the point (r,π - θ ) or (-r, -θ ) also lies on the graph.
3. Symmetry about the origin: If the point (r, θ ) lies on the graph, then the point (-r, θ ) or (r, π + θ ) also lies on the graph.
Put (r, -θ ) in the given function.
Therefore it is not symmetric about x-axis.
Put (-r, -θ ) in the given function.
Therefore it is symmetric about y-axis.
Put (-r,θ ) in the given function.
Therefore it is not symmetric about the origin.
Answer:
Step-by-step explanation:
Given
Solving (a): Point estimate of difference of mean
This is calculated as:
Solving (b): 90% confidence interval
We have:
Confidence level is:
Calculate
The z score is:
The endpoints of the confidence level is:
Split
Hence, the 90% confidence interval is:
Solving (c): 95% confidence interval
We have:
Confidence level is:
Calculate
The z score is:
The endpoints of the confidence level is:
Split
Hence, the 95% confidence interval is:
This is an example of conditional probability because we are trying to find the probability of an event occurring GIVEN the occurrence of some other event. There is a formula for this (see image attached).
If we follow this formula, the numerator would be the probability of (A AND B) which in this case is "48% of the class passed BOTH exams." The denominator in the formula would be that "60% of the class passed ONLY THE SECOND exam."
Therefore, P(A and B) = 0.48, which is 48% expressed as a decimal and P(B)= 0.60, which is 60% expressed as a decimal. Then, you can figure out the answer by dividing.
If we follow this formula, the numerator would be the probability of (A AND B) which in this case is "48% of the class passed BOTH exams." The denominator in the formula would be that "60% of the class passed ONLY THE SECOND exam."
Therefore, P(A and B) = 0.48, which is 48% expressed as a decimal and P(B)= 0.60, which is 60% expressed as a decimal. Then, you can figure out the answer by dividing.