4 years ago

Use ABC shown to the right to answer the following question if BK=21 what is KO

1 answer:

3 0

$BK = 2KQ\Leftrightarrow KQ = \frac{BK}{2} = \frac{21}{2} = 10.5$

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kondor19780726 [428]

Answer:

$\frac{f(x)}{g(x)}=3x^2+6x-2-\frac{12}{3x+1}$

Step-by-step explanation:

The first function is $f(x)=9x^3+21x^2-14$

The second function is $g(x)=3x+1$ .

$\frac{f(x)}{g(x)}=\frac{9x^3+21x^2-14}{3x+1}$

We perform the long division as shown in the attachment to obtain the quotient as: $Q(x)=3x^2+6x-2$ and remainder $R=-12$ .

Therefore:

$\frac{f(x)}{g(x)}=3x^2+6x-2-\frac{12}{3x+1}$

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