![\sf \longrightarrow \: f(x) = {x}^{2}](https://tex.z-dn.net/?f=%20%5Csf%20%5Clongrightarrow%20%5C%3A%20f%28x%29%20%3D%20%20%7Bx%7D%5E%7B2%7D%20)
Write the parent function in the standard form I.e.
![\boxed{ \tt \:y =a(x - h) \times 2 + k }](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%5Ctt%20%5C%3Ay%20%3Da%28x%20-%20h%29%20%5Ctimes%202%20%2B%20k%20%20%7D)
Where,
![\sf \longrightarrow \:y= 1(x - 0)^{2} \times 2 + 0](https://tex.z-dn.net/?f=%20%5Csf%20%5Clongrightarrow%20%5C%3Ay%3D%20%201%28x%20-%200%29%5E%7B2%7D%20%5Ctimes%202%20%2B%200)
![\sf \longrightarrow \: y = (x - 0) ^{2} \times 2 + 0](https://tex.z-dn.net/?f=%20%5Csf%20%5Clongrightarrow%20%5C%3A%20y%20%3D%20%28x%20-%200%29%20%5E%7B2%7D%20%20%5Ctimes%202%20%2B%200)
![\sf \longrightarrow \: y = {x}^{2} \times 2](https://tex.z-dn.net/?f=%20%5Csf%20%5Clongrightarrow%20%5C%3A%20y%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%20%5Ctimes%202)
![\sf \longrightarrow \: y = 2{x}^{2}](https://tex.z-dn.net/?f=%20%5Csf%20%5Clongrightarrow%20%5C%3A%20y%20%3D%20%202%7Bx%7D%5E%7B2%7D%20%20)
Answer:
The current deer population is 240.
Step-by-step explanation:
The expression given models a exponential decay follows:
![p(n) = 240*(0.978)^n](https://tex.z-dn.net/?f=p%28n%29%20%3D%20240%2A%280.978%29%5En)
For every year that passes since the beginning of the count the population is 0.978 of the year prior. Assuming that the count starts at this year, then "n" is equal to 0, applying this value of n to the formula gives us:
![p(0) = 240*(0.978)^0\\p(0) = 240*1 = 240](https://tex.z-dn.net/?f=p%280%29%20%3D%20240%2A%280.978%29%5E0%5C%5Cp%280%29%20%3D%20240%2A1%20%3D%20240)
The current deer population is 240.
Answer:
![y\in (-\infty ,5]](https://tex.z-dn.net/?f=y%5Cin%20%28-%5Cinfty%20%2C5%5D)
Step-by-step explanation:
In this problem, we need to write "Twenty times y is at most 100 in interval notation
".
20 times y means, 20y
Atmost means an inequality which is ![\le](https://tex.z-dn.net/?f=%5Cle)
ATQ,
![20\times y\le 100](https://tex.z-dn.net/?f=20%5Ctimes%20y%5Cle%20100)
i.e.
![20y\le 100\\\\y\le 5](https://tex.z-dn.net/?f=20y%5Cle%20100%5C%5C%5C%5Cy%5Cle%205)
We can also write it as :
![y\in (-\infty ,5]](https://tex.z-dn.net/?f=y%5Cin%20%28-%5Cinfty%20%2C5%5D)
Hence, the required interval notation is
.
Answer:
???????????//?///
Step-by-step explanation: