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Romashka-Z-Leto [24]
2 years ago
6

A particle moves along the x-axis so that at any time t≥0 its velocity is given by v(t)= t^2In(t+2). What is the acceleration of

the particle at time t=6
Mathematics
1 answer:
S_A_V [24]2 years ago
3 0
Acceleration is the change of velocity per unit change of time. In this case, given the velocity equation, we can get the acceleration of the particle by taking the first derivative of the equation. v'(t)= t^2 (1/t+2) + 2t In(t+2). substituting t= 6, acceleration is equal to 29.45 m/s2.
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olganol [36]

Answer:

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Explanation:

We have been given with the quadratic equation x^2-7x-6=0

We have general formula to find the roots of a quadratic equation first we find the discriminant with formula

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and after that to find the variable suppose x we have the formula

x=\frac{-b\pm\sqrt{D}} {2a}

And general quadratic equation is

ax^2+bx+c=0

On comparing the given quadratic equation with genral quadratic equation we will have values

a=1, b=-7 and c=-6

After substituting these values in the formula we will get  

D=(-7)^2-4(1)(-6)={73}

After substituting in the formula to find x we will get

\frac{-(-7)\pm\sqrt{73}} {2}= \frac{7\pm\sqrt{73}} {2}

4 0
3 years ago
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RideAnS [48]

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Step-by-step explanation:

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Multiplying by 24 oz, we get ...

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Ellen pays $2.85 for the beans.

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Pepsi [2]

Answer:

Step-by-step explanation:

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