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Romashka-Z-Leto [24]
3 years ago
6

A particle moves along the x-axis so that at any time t≥0 its velocity is given by v(t)= t^2In(t+2). What is the acceleration of

the particle at time t=6
Mathematics
1 answer:
S_A_V [24]3 years ago
3 0
Acceleration is the change of velocity per unit change of time. In this case, given the velocity equation, we can get the acceleration of the particle by taking the first derivative of the equation. v'(t)= t^2 (1/t+2) + 2t In(t+2). substituting t= 6, acceleration is equal to 29.45 m/s2.
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In order to solve for a nth term in an arithmetic sequence, we use the formula written as:<span>

an = a1 + (n-1)d

where an is the nth term, a1 is the first value in the sequence, n is the term position and d is the common difference.

First, we need to calculate for d from the given values above.  
<span>a3 = 20.5 and a8 = 13
</span>

an = a1 + (n-1)d
20.5 = a1 + (3-1)d

</span>an = a1 + (n-1)d
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<span>
a1 = 23.5
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The 11th term is calculated as follows:

a11 = a1 + (n-1)d
a11= 23.5 + (11-1)(-1.5)
a11 = 8.5</span>
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Step-by-step explanation:

Remember to follow FOIL.

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Finally, multiply the last. (-9)(2) = -18

Combine like terms: x² + 2x - 9x - 18

x² - 7x - 18

x² - 7x - 18 is your answer.

~

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