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Romashka-Z-Leto [24]
3 years ago
6

A particle moves along the x-axis so that at any time t≥0 its velocity is given by v(t)= t^2In(t+2). What is the acceleration of

the particle at time t=6
Mathematics
1 answer:
S_A_V [24]3 years ago
3 0
Acceleration is the change of velocity per unit change of time. In this case, given the velocity equation, we can get the acceleration of the particle by taking the first derivative of the equation. v'(t)= t^2 (1/t+2) + 2t In(t+2). substituting t= 6, acceleration is equal to 29.45 m/s2.
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andrew-mc [135]

Answer:

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Step-by-step explanation:

So, this question involves you to play around with the numbers and the operations a bit. I've come up with a solution, but perhaps there are others as well.

So, we have:

7\text{ } 11\text{ } 4\text{ } 2\text{ } =\text{ } 10

So, what we can do is, for instance, multiply 4 and 2. Subtract that into 11. And then add the difference to 7. Thus:

7+(11-4\times 2)=10

This is a true number sentence. Let's do it to make sure.

First, do the operations inside the parentheses.

Multiplication comes first, so multiply:

7+(11-8)=10

Again, do the parentheses first. Subtract:

7+(3)=10

Now add:

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