the longest side of an acute isosceles triangle 8 centimeters . Round to the nearest tenth, what is the smallest possible length
2 answers:
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Answer:
look the photo
Step-by-step explanation:
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Answer:
A ≈ 40.3 cm²
Step-by-step explanation:
The area of right Δ ACD is calculated as
A = bh ( b is the base and h the perpendicular height )
Here A = 50.5, b = CD and h = AC , then
× 14 × AC = 50.5
7 AC = 50.5 ( divide both sides by 7 )
AC ≈ 7.214
The area of Δ ABC is calculated as
A = × BC × AC × sin36°
= 0.5 × 19 × 7.214 × sin36°
≈ 40.3 cm² ( to 3 sf )
The acronym for trigs is SOH CAH TOA
Sine means opposite divided by hypotenuse
So, let us find sine.
The opposie side is 16
The hypotenuse is 17.46
Use your calculator
The answer is ≈ 0.9164
Sine means opposite divided by hypotenuse
So, let us find sine.
The opposie side is 16
The hypotenuse is 17.46
Use your calculator
The answer is ≈ 0.9164