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dlinn [17]
3 years ago
14

Need help evaluating the limits for this problem.

Mathematics
1 answer:
TEA [102]3 years ago
4 0

Answer:

  • a)  c
  • b)  c
  • c)  c
  • d)  DNE

Step-by-step explanation:

There is nothing about the definition of q(x) that keeps you from evaluating the limit by substituting the value b for x in the appropriate definition.

a) from the left: lim = a(b -b)^3 +c = 0 + c = c

b) from the right: lim = a(b -b) +c = 0 + c = c

c) the limit from the left is equal to the limit from the right, so the limit exists and is that value: c.

d) the function is undefined at x=b, so q(b) does not exist. (The graph has a hole at that point.)

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An athlete knows that when she jogs along her neighborhood​ greenway, she can complete the route in 10 minutes. It takes 20 minu
IgorLugansk [536]

Answer:

10 miles per hour.

Step-by-step explanation:

Let x represent athlete's walking speed.

We have been given that her jogging rate is 5 mph faster than her walking​ rate, so athlete's jogging speed would be x+5 miles per hour.

\text{Distance}=\text{Rate}\cdot \text{Time}

10 minutes = 1/6 hour.

20 minutes = 1/3 hour

While walking, we will get D_{\text{walking}}=x\frac{\text{miles}}{\text{hour}}\cdot \frac{1}{3}\text{hour}

D_{\text{walking}}=\frac{x}{3}

While jogging, we will get D_{\text{jogging}}=(x+5)\frac{\text{miles}}{\text{hour}}\cdot \frac{1}{6}\text{hour}

D_{\text{jogging}}= \frac{(x+5)}{6}

Since athlete is covering same distance while walking and jogging, so we can equate both expressions as:

\frac{x}{3}=\frac{x+5}{6}

Cross multiply:

6x=3x+15

6x-3x=15

3x=15

\frac{3x}{3}=\frac{15}{3}\\\\x=5

Therefore, athlete's walking speed is 5 miles per hour.

Jogging speed: x+5\Rightarrow 5+5=10

Therefore, athlete's jogging speed is 10 miles per hour.

3 0
3 years ago
Pls look at picture and answer
Kay [80]

Answer:

i cant see the picture

Step-by-step explanation:

it looks pretty blurry

3 0
3 years ago
One hundred voters were asked whether they supported a bill that had
rodikova [14]

The question is cut off.

7 0
2 years ago
What is the measure of L in
kolezko [41]

Use trigonometry to find L.

Tangent = opposite over adjacent on any right triangle.

tan(L) = 18/23

Take the inverse on both sides.

arctan(tan(L)) = arctan(18/23)

L = 38.0470425318

L = 38.05°

Done.

6 0
3 years ago
What is -5t+7=11t+25 solved
skad [1K]
The answer is t=2!!!!!!
6 0
3 years ago
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