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fgiga [73]
4 years ago
15

Can ocean currents be caused by differences in water temperature

Chemistry
1 answer:
Digiron [165]4 years ago
6 0

Answer: Winds and currents flow faster at the equator than at the poles. One reason equatorial currents are faster is that they are warmer. Another reason is that the speed of the Earth's rotation is much faster at the equator.

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How can the atomic number and mass number be used to determine the amount of each subatomic particle present in an atom of a giv
Goshia [24]
Because of the environment that
4 0
4 years ago
A 25.0 liter rigid container has a mixture of 32.00 grams of oxygen gas and 1 point
Ksivusya [100]

Answer:

P_{T} = 2.94 atm

Explanation:

The total pressure (P_{T}) in the container is given by:

P_{T} = P_{O_{2}} + P_{He}

The pressure of the oxygen (P_{O_{2}}) and the pressure of the helium (P_{He}) can be calculated using the ideal gas law:

PV = nRT

<u>Where</u>:

V: is the volume = 25.0 L

n: is the number of moles of the gases

R: is the gas constant = 0.082 Latm/(Kmol)

T: is the temperature = 298 K

First, we need to find the number of moles of the oxygen and the helium:

n_{O_{2}} = \frac{m}{M}

Where m is the mass of the gas and M is the molar mass

n_{O_{2}} = \frac{32.00 g}{31.998 g/mol} = 1.00 moles  

And the number of moles of helium is:

n_{He} = \frac{8.00 g}{4.0026 g/mol} = 2.00 moles

Now, we can find the pressure of the oxygen and the pressure of the helium:

P_{O_{2}} = \frac{nRT}{V} = \frac{1.00 moles*0.082 Latm/(Kmol)*298 K}{25.0 L} = 0.98 atm

P_{He} = \frac{nRT}{V} = \frac{2.00 moles*0.082 Latm/(Kmol)*298 K}{25.0 L} = 1.96 atm

Finally, the total pressure in the container is:

P_{T} = P_{O_{2}} + P_{He} = 0.98 atm + 1.96 atm = 2.94 atm

Therefore, the total pressure in the container is 2.94 atm.

I hope it helps you!

6 0
4 years ago
Balancing chemical equations
lubasha [3.4K]

Answer:

Where is your question? I do not see it.

Explanation:

4 0
4 years ago
Thymolphthalein is an indicator that changes color over a range from pH=9.3 to pH=10.5. What is Ka of thymolphthalein?
Likurg_2 [28]
According to Hasselbalch equation pH = pKa at the equal point. When pH equals the pKa value of the indicator, the base and acid forms of indicator are present in the ratio of 1:1 

(9.3 + 10.5) / 2 =9.9
pKa = 9.9
Using the equation pH = pKa at equal point we get
Ka = 10^- pKa
Ka = 10^- 9.9
Ka = 1.26 x 10^-10
Ka = 1 x 10^-10

6 0
3 years ago
A 3.689 g object is added to 7.29 mL of water causing The water level to rise to 8.54 ML. What is the density of the object? Rou
Marina CMI [18]

Answer:

2.95 g / mL

Explanation:

For this problem, we will simply use the equation that density is equivalent to mass over volume.  We are given the mass of the object and the initial and final volumes of water in the cylinder.  Thus we can find the density as such:

Density = Mass / ( Final Volume - Initial Volume )

Density = 3.689 g / ( 8.54 mL - 7.29 mL )

Density = 3.689 g / ( 1.25 mL )

Density = 2.9512 g / mL

Hence, the density of the object is 2.9512 g / mL.

Cheers.

7 0
4 years ago
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