Answer:
5.36 grams the mass in grams of zinc nitrate the chemist has added to the flask.
Explanation:

Moles of zinc nitrate = n
Volume of the solution = 135.0 mL = 0.1350 L
Molarity of the solution = 0.21 M


Mass of 0.02835 moles of zinc nitrate:
0.02835 mol × 189 g/mol = 5.358 g ≈ 5.36 g
5.36 grams the mass in grams of zinc nitrate the chemist has added to the flask.
Explanation:
hope it helps you understand moles
D = M/V
D = 0.10
V = 1000 cm^3
0.10 = M / 1000
M = 100
Porque la densidad es 10%, se puede usar 0.10 en este formulario para calcular el peso. No sé lo que es la unidad para el peso pero es 100.
For plato users
the answer is a. O2(l) O2(g)
hope this helps!
Answer:
24 mol Cu
General Formulas and Concepts:
<u>Chemistry</u>
Explanation:
<u>Step 1: Define</u>
RxN: 2Cu (s) + O₂ (g) → 2CuO (s)
Given: 12 moles O₂
<u>Step 2: Stoichiometry</u>
<u />
= 24 mol Cu
<u>Step 3: Check</u>
<em>We are given 2 sig figs.</em>
Our final answer is in 2 sig figs, so no need to round.