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solmaris [256]
3 years ago
8

In the molecule SF4, sulfur makes four covalent bonds. Therefore, four of its six valence electrons need to be unpaired. The orb

itals with the same energy are known as degenerate orbitals. For example, the p subshell has three degenerate orbital, namely, px, py, and pz. How many degenerate orbitals are needed to contain six electrons with four of them unpaired?

Chemistry
1 answer:
Bezzdna [24]3 years ago
3 0

Explanation:

As it is given that there are six electrons with four of them unpaired in the degenerate orbital.

As in a p-orbital there are only 3 sub-orbitals, that is, p_{x}, p_{y}, and p_{z}. In these sub-orbitals, a maximum of 6 electrons can be accommodated.

Th next higher orbital is d-orbital which can contain a maximum of 10 electrons. There are 5 degenerate orbitals present in a d-orbital.

So, a d-orbital can easily accommodate six electrons with four of them unpaired.

Thus, we can conclude that 5 degenerate orbitals are needed to contain six electrons with four of them unpaired.

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The neutral atom of lead must have 82 protons while ions can have b or less than 82.

The atomic number of an element is the number of protons in the nucleus of the element.

Also, for neutral atoms, the number of protons equals the number of electrons.

In ionic form, the number of protons/electrons of an atom may vary and be different from that of the neutral form.

Positive charges mean that the ion has less proton than its neutral version while negative charges mean that it has more electrons than its neutral version.

Thus, the neutral atom of lead will contain an equal number of protons as the electrons while its ionic form can have more or less than 82 protons.

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