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3 years ago

What volume of concentrated nitric acid (15.0 M) is

Chemistry

1 answer:

soldier1979 [14.2K]3 years ago

6 0

Answer:

130 μL

Explanation:

The dilution formula is used to calculate the volume V₁ required:

C₁V₁ = C₂V₂

V₁ = (C₂V₂)/C₁ = (2.00L)(0.001M)/(15.0M) = 1.3 x 10⁻⁴ L or 130 μL

(1.3 x 10⁻⁴ L)(10⁶ μL/L) = 130 μL

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Write any two limitations of formula equation

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Following are the limitations of a chemical equation: (i) A chemical equation does not tell us the physical state of the reactants and the products in the reaction. (ii) It does not tell us the actual concentration or dilution of the reactants used in the reaction

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3 years ago

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At 298 K and 1 atm, bromine is a liquid with a high vapor pressure, whereas chlorine is a gas. This provides evidence that, unde

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Explanation:

In liquids, the molecules are held by less strong intermolecular forces of attraction as compared to solids. Due to which they are able to slide past each other. Hence, they have medium kinetic energy.

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So, when at 298 K and 1 atm $Br_{2}$ exists in liquid state and $Cl_{2}$ exists as a gas then it means there occurs strong force of attraction between the molecules of $Br_{2}$ due to which it exists in liquid form.

Thus, we can conclude that at 298 K and 1 atm, bromine is a liquid with a high vapor pressure, whereas chlorine is a gas. This provides evidence that, under these conditions, the forces among $Br_2$ molecules are greater than those among $Cl_2$ molecules.

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3 years ago

If you combust 7.500g of methanol with an excess of oxygen, a) how many grams and molecules of water will be produced, and b) ho

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Explanation:

The equation for this reaction is given by;

2CH3OH(l) + 3O2(g) → 2CO2(g) + 4H2O(g)

From the reaction;

2 mol of methanol produces 2 mol of CO2 and 4 mol of water

In terms of mass;

Mass = Molar mass * Number of mol

Methanol;

Mass = 32 g/mol * 2 mol = 64 g

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Mass = 44 g/mol * 2 mol = 88g

H2O;

Mass = 18 g/mol * 4 mol = 72 g

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64g of methanol produces 88g of CO2 and 72g of water

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64g of Methanol = 72g of Water

7.5g would produce xg of Water

X = (7.5 * 72) / 64 = 8.4375 g of water

Number of moles = Mass / Molar mass = 8.4375 / 18 = 0.46875 mol

Molecules = moles * Avogadro number = 0.46875 * 6.022 * 10^23 = 2.82 * 10^23 molecules

b) how many grams and molecules of carbon dioxide will be produced

64g of Methanol = 88g of CO2

7.5g would produce xg of CO2

X = (7.5 * 88) / 64 = 10.3125 g of CO2

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3 years ago

Without the mitochondria, cells would _____.

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4 years ago

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Answer:

See explanation below

Explanation:

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C) False

D) True

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G) True

H) True ( repeated question)

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