Prob of selected students times prob of selecting boys times prob of selecting 3 boys
total students = 15b + 30g = 45 students
1. 10s/45t = 0.22
2. 15b/45t = 0.33
3. 3b/15b = 0.2
0.22×0.33×0.2=0.0148
1.48%
I'm not sure 100%... double check answer please
All four angles are exterior angles of the quadrilateral.
We know that the sum of exterior angles of any polygon is 360 ° .
So we can add together the four angles and solve for x:
(x+16)+(3x-1)+6x+5x = 360
15x+15=360
15x=345
x=345/15=23 °
Answer:
a. The time to strike the ground is 5 seconds
b. The time for the ball to be over than 96 ft is 1 second
Step-by-step explanation:
a. When the ball thrown vertically up ward to reach its maximum height at velocity = 0 then complete its motion vertically down ward to strike the ground its displacement = zero
∴ s(t) = 0 ⇒ 
∴
5 - t = 0⇒ ∴ t = 5 seconds
b. To tind the time that the ball will be over 96 ft over the ground substitute in 
t = 3 sec. and t = 2 sec.
The ball will be at height 96 ft at time 2 sec. and 3 sec.
So the ball will be at height over than 96 = 3 - 2 = 1 sec.
Answer:
The slope is 3 and the y intercept is -7/4
Step-by-step explanation:
We need to get the equation in the form
y = mx+b where m is the slope and b is the y intercept
12x - 4y =7
Subtract 12x from each side
12x-12x -4y = -12x +7
-4y = -12x+7
Divide each side by -4
-4y/-4 = -12x/-4 +7/-4
y = 3x + -7/4
The slope is 3 and the y intercept is -7/4
