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3 years ago

What is the area of a parallelogram whose vertices are A(−12, 2) , B(6, 2) , C(−2, −3) , and D(−20, −3) ?

2 answers:

7 0

I am finding the answer right now but there is a website that you can use for math that really helps. It's called Desmos.

lukranit [14]3 years ago

5 0

These have two sides with constant y values, i.e. two sides parallel to the x axis. We'll check they're the same length

AB=6 - -12 = 18

CD = -2 - -20 = 18 good

That's the base. The height is 2 - -3 = 5 so an area of 18(5)=90

Answer: 90

Even if we didn't know it was a nicely oriented parallelogram we can get the area with the shoelace formula, which says it's half the absolute value of the sum of the cross products of each side.

A(−12, 2) , B(6, 2) , C(−2, −3) , D(−20, −3)

B(6, 2) , C(−2, −3) , D(−20, −3) , A(−12, 2)

A = (1/2) | (-12)(2) - 2(6) + 6(-3) - 2(-2) + (-2)(-3) - (-3)(-20) + (-20)(2) - (-3)(-12) | = |-180|/2 = 90

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3 years ago

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Step-by-step explanation:

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In this case a paired t-test is used to determine the effectiveness of garlic for lowering cholesterol.

A random sample of 81 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment.

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3 years ago

The diagram represents a reduction of a triangle by using a scale factor of 0.8.

Alekssandra [29.7K]

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Step-by-step explanation:

See comment for complete question

Represent the larger triangle with 1 and the smaller with 2.

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To do this we apply dilation formula.

$Original * Scale\ Factor = New$

In this case:

$H_1 * Scale\ Factor = H_2$

Substitute 6 for H1 and 0.8 for Scale Factor

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$4.8= H_2$

Hence, the height of the smaller triangle is 4.8 inches

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