Answer:
5/ 18
Explanation:
Given :
List A: [20,10,20]
List B: [40,10,30,20,40,30]
Chance that number drawn from list A is larger than or equal to that drawn dlfrom list B.
If:
A = 20
B ≤ 20 : [10,20] = 2
A = 10
B ≤ 10 : [10] = 1
A = 20
B ≤ 20 : [10,20] = 2
Probability = Required outcome / Total possible outcomes
Hence,
required outcome = (2 + 2 +1) = 5
Total possible outcomes = 3C1 * 6C1 = (3 * 6) = 18
Hence,
chance that the number we drew from list A is larger than or equal to the number we drew from list B
= 5 / 18
Answer:
You can use Outlook to perform diffrent aspects
In the toolbox command
Answer:
This question is answered using Java programming language:
public static void print10(String[]arr){
for(int i =0; i<10;i++){
System.out.println(arr[i]);
}
}
Explanation:
This line defines the method
public static void print10(String[]arr){
This iterates from 0 to 9 index of the array. In other words, 1st to 10th
for(int i =0; i<10;i++){
This prints the required output (one on a line)
System.out.println(arr[i]);
}
}
<em>Refer to attachment for the complete program that includes the main method.</em>
