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nekit [7.7K]
3 years ago
11

How many moles are in 155 grams of aluminum

Chemistry
1 answer:
MArishka [77]3 years ago
7 0

Answer:

2.06 aluminium ions in the sample, due to the chemical formula.

Explanation:

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Calculate the mass of water vapour present in a room of volume 400 m3 that contains air at 27 °C on a day when the relative humi
Alex73 [517]

Answer:

Mass of water = 6251. 706g or 6.25Kg

Explanation:

Relative humidity = (actual vapor pressure/saturation vapor pressure) * 100%

Actual vapor pressure, Pw = relative humidity * saturation vapor pressure

Pw = 60% * (35.6 *0.001)atm = 0.0216atm

Note: 1mbar = 0.001atm

Using the ideal gas equation: PV=nRT; where P = Pw= 0.02136atm, V= (400

* 1000)dm^3, R= 0.082 atmdm^3/kmol, T= (27+273)K, n = number of moles

Note: 1m^3 = 1000dm^3,R is the molar gas constant.

Making n subject of the formula, n = PV/RT

n= (0.02136 * 400000)/(0.082 * 300) = 347.317 moles

Mass (g) = number of moles (n) * molar mass

molar mass of water=18g

Mass of water = 347.317 * 18 = 6251. 706g or 6.25Kg

6 0
3 years ago
1. Which of the following pairs of factors affects the solubility of a particular substance? (1 point)
Lina20 [59]
<h2>Question no 1:</h2><h3>Answer:</h3>

The correct answer is option A which is temperature and the nature of solute and solvent

<h3>Explanation:</h3>
  • The solubility of a substance is its ability to dissolve in a particular solution.
  • Solubility is highly dependent on the temperature and nature of solute and solvent.
  • It is directly proportional to the temperature. As we increase the temperature, the solubility of substantial increases but for the exothermic reactions, solubility is inversely proportional to temperature.
  • Solubility is absolutely dependent on the nature of solute and solvent, as polar solute and solvents have high solubility than non polar.
<h2>Question no. 2</h2><h3>Answer:</h3>

The correct answer is option B which is a large amount of solute.

<h3>Explanation:</h3>
  • A concentrated solution contains the maximum amount of solute which can be dissolved in the solvent.
  • For example, in water sugar solution concentrated solution will contain a large amount of sugar dissolved in water without the addition of heat.
  • In dilute solution, there is a small amount of solute.
<h2>Question no. 3:</h2><h3>Answer:</h3>

The correct answer is option B which is molarity × liters of solution.

<h3>Explanation:</h3>

Molarity of a solution is the total number of moles of solute per unit volume of solution.

Its formula is:

             Molarity = Number of moles of the solute/volume of solution in liters.

    A number of moles of solute =  Molarity × Volume of the solution.

So the number of moles of solute is equal to the molarity and volume of solution. Hence correct option is B.

<h2>Question no 4.</h2><h3>Answer:</h3>

The correct answer is option D. Molarity of the dilute solution = 0.81 M

<h3>Explanation:</h3>

Given data:

        initial volume = V1 = 225 mL = 0.225 L

        Initial molarity = M1 = 0.80M

        Final volume =  V2 = 1 L

        Final molarity  = M2 = ?

Solution:

It is the dilution of the stock solution and the formula is given below:

V1M1 = V2M2

M2 = V1.M1/V2

By putting values in the formula:

M2 = 0.225 × 0.8/1

M2= 0.18

So the final molarity of the solution will be 0.18 M. Hence the correct answer is option D.

<h2>Question no. 5</h2><h3>Answer:</h3>

The correct answer is option B which is supersaturation.

<h3>Explanation:</h3>
  • Colligative properties of the solution are the properties which are not dependent on the number of particles of the solute in the solution.
  • While supersaturation of the solution means the solution containing the highest number of solute particles dissolved in the solution.
  • Since supersaturation is dependent on a number of solutes, it is not a colligative property.
<h2>Question no 6.</h2><h3>Answer:</h3>

The correct answer is option B/C, "which disrupts crystal formation of the solvent".

<h3>Explanation:</h3>
  • Depression of freezing point is the colligative property of the solution.
  • Which the lowering of the freezing point of a solution by adding the solute.
  • The addition of solute disrupts the crystal formation in the solvent, as it disrupts the intermolecular forces between solute particles.
  • Hence option B and C are the correct options because both have the same statement.
<h2>Question no 7.</h2><h3>Answer:</h3>

The correct answer is option D which is 142.

<h3>Explanation:</h3>

<u>Given data:</u>

Volume of solution = 167 ml

Percentage of solution = 85%

The volume of alcohol =?

<u>Solution:</u>

Percentage of solution ( v/v) = volume of solute/volume of solution × 100

The volume of solute = percentage × volume of solution/100

By putting values in above formula:

Volume of alcohol = 85 × 167/100 = 141.95 ml

<em><u>Hence the correct answer is option D which is approximately 142(141.95).</u></em>

8 0
2 years ago
Read 2 more answers
The reaction in which methane is burned, CH4 +202 --&gt; 2H20 + CO2, is an example of a
alexira [117]

Answer: Combustion

Explanation:

Methane gas or natural gas is the hydrocarbon that reacts with oxygen as shown below: CH4 + 2O2 → CO2 + 2H2O There are two types of combustion reactions: complete and incomplete combustion. Therefore there are four products, carbon dioxide, water, carbon, and carbon monoxide.

8 0
3 years ago
what is the percent by mass of a solution that contains 30 grams of potassium nitrite in 0.5 kilograms of water?
Makovka662 [10]

Answer:

5.66 %.

Explanation:

<em>mass percent is the ratio of the mass of the solute to the mass of the solution multiplied by 100.</em>

<em />

<em>mass % = (mass of solute/mass of solution) x 100.</em>

<em></em>

mass of potassium nitrite = 30.0 g,

mass of the solution = mass of water + mass of potassium nitrite = 500.0 g + 30.0 g = 530.0 g.

<em>∴ mass % = (mass of solute/mass of solution) x 100</em> = (30.0 g/530.0 g) x 100 = <em>5.66 %.</em>

5 0
3 years ago
What identifies a flaw in J. J. Thomson’s model of the atom?
katrin [286]

Answer:

The plum-pudding model did not identify a central nucleus as the source of a positive charge.

Explanation:

Sir Joseph John Thomson, most popularly known as J J Thomson. He was a famous scientist who was awarded the Noble prize for Physics for his discovery of the subatomic particle, electron.

He placed his famous model of an atom which is known as plum pudding model. He proposed that the atoms are described as the negative particles that is floating within a soup of the diffuse positive charge.

But the main defect of his proposal was that it did not recognized the presence of a central nucleus as a positive charged source.

3 0
2 years ago
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