Answer:
What will happen to Uk if you double the mass?
Explanation:
Uk = 0.5 * m * v²
You see that both m and v are variable, which means that both m and v can be any number. Regardless of the numbers you put in for m or v, the formula to calculate the kinetic energy (Uk) remains valid.
You could ask
1. What will happen to Uk if you double the mass?
2. What will happen to Uk if you double the velocity?
please see and understand(!) that the relationship between Uk an v² is indeed the velocity squared....
EXTRA
Uk = 0.5 * m * (v)²
Suppose the m = 3kg and velocity = 5 m/s
What is the Uk?
Well if you know the formula you can use your calculator to find out:
Uk = 0.5 * m * (v)²
Uk = 0.5 * 3 * (5)²
Uk = 0.5 * 3 * 25
Uk = 37.5 kgm/s²
Again you ask what will happen to Uk if you double the velocity?
At first it was 5 m/s and now it doubles, which means it now has that value *2
The new velocity is 5 *2 = 10 m/s
Uk = 0.5 * m * (v)²
Uk = 0.5 * 3 * (10)²
Uk = 0.5 * 3 * 100
Uk = 150 kgm/s²
150 = 4 * 37.5
So now you see that if you double your velocity, the Uk will be 2² = 4 times as big !
Answer: -
4.25 mol of O₂ left as excess.
3.5 mol of NO₂ formed.
Explanation: -
Number of moles of NO taken = 3.5
Number of moles of O₂ taken = 6.0
The balanced chemical equation for this reaction is
2 NO+ O₂ → 2 NO₂
From the equation we can see that
2 mol of NO react with 1 mol of O₂
3.5 mol of NO react with 
x 3.5 mol NO
= 1.75 mol O₂
So Oxygen O₂ is in excess and NO is the limiting reagent.
Moles of O₂ left over = 6 - 1.75 =4.25 mol of O₂
From the balanced chemical equation we see
2 mol of NO gives 2 mol of NO₂
3.5 mol of NO gives
x 3.5 mol NO
= 3.5 mol of NO₂
Answer: ![[OH^{-}]= 0.01M or 1.0\times 10^{-2}M](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%5D%3D%200.01M%20or%201.0%5Ctimes%2010%5E%7B-2%7DM)
![[H^{+}]= 1.0\times 10^{-12}M](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%3D%201.0%5Ctimes%2010%5E%7B-12%7DM)
pH = 12
pOH = 2
Explanation: Calcium hydroxide (
) is a strong base that dissociates completely.
Dissociation equation of Calcium hydroxide is :
1. Concentration of [OH-]
1 mol produces 2 mol OH- ions.
The given solution is 0.005M , then concentration of OH- would be twice the concentration of
![[OH^{-}] = 0.005\times 2](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%5D%20%3D%200.005%5Ctimes%202%20)
= 0.01M or 
2.Concentration of [H+]
Concentration of [H+] can be calculated by the formula: ![[H^{+}] = \frac{Kw}{[OH^{-}]}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%20%5Cfrac%7BKw%7D%7B%5BOH%5E%7B-%7D%5D%7D)
kw = ionic product of water and its values is 
[OH-] = 0.01 M or
![[H^{+}] = \frac{(1\times 10^{-14})}{[OH^{-}]}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%20%5Cfrac%7B%281%5Ctimes%2010%5E%7B-14%7D%29%7D%7B%5BOH%5E%7B-%7D%5D%7D)
![[H^{+}] = \frac{(1\times 10^{-14})}{[0.01]}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%20%5Cfrac%7B%281%5Ctimes%2010%5E%7B-14%7D%29%7D%7B%5B0.01%5D%7D)
![[H^{+}] = 1.0\times 10^{-12}M](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%201.0%5Ctimes%2010%5E%7B-12%7DM%20)
3. pH value
pH is calculated by the formula : ![pH = -log[H^{+}]](https://tex.z-dn.net/?f=pH%20%3D%20-log%5BH%5E%7B%2B%7D%5D)
![pH = -log[1.0\times 10^{-12}]](https://tex.z-dn.net/?f=pH%20%3D%20-log%5B1.0%5Ctimes%2010%5E%7B-12%7D%5D)
pH = 12
4. pOH value
pOH is calculated by the formula : pOH = 14 - pH
pOH = 14 - 12
pOH = 2
pOH can also be calculated by using a different formula which is :
pOH = 2.
Red, Orange, Yellow, Green, Blue, Violet and Indigo
Answer:
Explanation:
Covalent bonding occurs when pairs of electrons are shared by atoms. Atoms will covalently bond with other atoms to gain more stability, which is gained by forming a full electron shell. By sharing their outermost (valence) electrons, atoms can fill up their outer electron shell and gain stability.
