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Elina [12.6K]
3 years ago
6

Which rule is used when writing the name of an ionic bass

Chemistry
2 answers:
jonny [76]3 years ago
8 0
The chemical name begins with Hydro The Chemical name ends with hydroxide and the ide ending is changed to ic also the polyatomic ate ending changed to ic
musickatia [10]3 years ago
6 0

Answer:

Name = name of metal + hydroxide.  

Step-by-step explanation:

You name an ionic base according to the rule:

Name = name of metal + hydroxide

Thus,  

  NaOH = sodium hydroxide

Ca(OH)₂ = calcium hydroxide

Al(OH)₃ = aluminium hydroxide

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7 0
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It is logical to conclude that water cannot dissolve vegetable oil because the oil is
Gekata [30.6K]
In chemistry, there is a common note that says, "Like dissolves like".

This pertains to the concept that polar substances can dissolve only other polar substances. Also, nonpolar substances are also only able to dissolve nonpolar substances. 

Polarity of the substance depends primarily on the type of bond and the difference in electronegativity. 

Water is a polar substance while vegetable oil is not. From the concept presented above, it may be concluded that water will not be able to dissolve the vegetable oil and the assumption is logical. 
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If 3.75 moles of aluminum react, how many moles of sulfur are needed?
aliya0001 [1]

Answer:(A) 0.70 mol

Explanation:

5 0
3 years ago
If 5.85 moles of CaCO3 are used in an experiment, how many moles of carbon dioxide are created? (Be sure to include units in you
azamat

Answer:

5.85 moles of carbon dioxide are created.

Explanation:

The balanced reaction is:

CaCO₃ → CaO + CO₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • CaCO₃: 1 mole
  • CaO: 1 mole
  • CO₂: 1 mole

Then you can apply the following rule of three: if by stoichiometry 1 mole of CaCO₃ produces 1 mole of CO₂, 5.85 moles of CaCO₃ will produce how many moles of CO₂?

moles of CO_{2}=\frac{5.85 moles of CaCO_{3} *1mole of CO_{2} }{1 mole of CaCO_{3}}

moles of CO₂= 5.85

<u><em>5.85 moles of carbon dioxide are created.</em></u>

7 0
3 years ago
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