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Snowcat [4.5K]
3 years ago
14

If 5.85 moles of CaCO3 are used in an experiment, how many moles of carbon dioxide are created? (Be sure to include units in you

r answer.) CaCO3 → CaO + CO2
Chemistry
1 answer:
azamat3 years ago
7 0

Answer:

5.85 moles of carbon dioxide are created.

Explanation:

The balanced reaction is:

CaCO₃ → CaO + CO₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • CaCO₃: 1 mole
  • CaO: 1 mole
  • CO₂: 1 mole

Then you can apply the following rule of three: if by stoichiometry 1 mole of CaCO₃ produces 1 mole of CO₂, 5.85 moles of CaCO₃ will produce how many moles of CO₂?

moles of CO_{2}=\frac{5.85 moles of CaCO_{3} *1mole of CO_{2} }{1 mole of CaCO_{3}}

moles of CO₂= 5.85

<u><em>5.85 moles of carbon dioxide are created.</em></u>

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What is the molar solubility of aucl3 (ksp = 3. 2 x 10-23) in a 0. 013 m solution of magnesium chloride (a soluble salt)?
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The molar solubility of AuCl₃ in a 0.013 M solution of magnesium chloride is 1.81×10⁻²⁸M.

<h3>What is Ksp?</h3>

The solubility product constant, Ksp, is the equilibrium constant for a solid substance dissolving in an aqueous solution. And for the AuCl₃, Ksp will be written as: Ksp = [Au³⁺][Cl⁻]³

Let the solubility of the AuCl₃ in 0.013M solution of magnesium chloride is x, of Au³⁺ is x and of Cl⁻ is 3x. But we know that MgCl₂ is a strong electrolyte and it completely dissociates into its ions and will produce 2 moles of chloride ions. For this solution let we consider the volume is 1 liter then the concentration of chloride ions in MgCl₂ is 2(0.013)=0.026M.

So, in MgCl₂ solution concentration of Cl⁻ becomes = 3x + 0.026.

Value of Ksp for AuCl₃ = 3.2 × 10⁻²³

On putting all values on the Ksp equation, we get

Ksp = (x)(3x + 0.026)³

Value of 3x is negligible as compared to the 0.026, so the equation becomes

3.2 × 10⁻²³ = (x)(0.026)³

x = 3.2×10⁻²³ / (0.026)³

x = 1.81×10⁻²⁸M

Hence the molar solubility of AuCl₃ in 0.010M MgCl₂ is 1.81×10⁻²⁸M.

To know more about molar solubility, visit the below link:

brainly.com/question/27308068

#SPJ4

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