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3 years ago

It is logical to conclude that water cannot dissolve vegetable oil because the oil is

Chemistry

2 answers:

marin [14]3 years ago

6 0

Answer:

The oil is insoluble with water.

Explanation:

The water and oil do not mix, they are illustrated as immiscible. The molecules of water are polar, that is, they exhibit a small positive charge at one terminal and a small negative charge at the other terminal, and they attach with each other. The molecules of oil are non-polar, and they possess no charge. Due to this, the molecules of oil are more fascinated with each other than to the molecules of water, and the molecules of water are more fascinated towards each other than to the molecules of oil.

Gekata [30.6K]3 years ago

3 0

In chemistry, there is a common note that says, "Like dissolves like".

This pertains to the concept that polar substances can dissolve only other polar substances. Also, nonpolar substances are also only able to dissolve nonpolar substances.

Polarity of the substance depends primarily on the type of bond and the difference in electronegativity.

Water is a polar substance while vegetable oil is not. From the concept presented above, it may be concluded that water will not be able to dissolve the vegetable oil and the assumption is logical.

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Mg (s) + 2 HCl (aq) --> MgCl2 (aq) + H2 (g)

Lera25 [3.4K]

Answer:

m = 190. g MgCl2

Explanation:

Use a molar ratio to get the # of moles MgCl2 produced from 4.00 mol of HCl:

4.00 mol HCl × (1 mol MgCl2/2 mol HCl) = 2.00 mil MgCl2

So 2.00 moles of MgCl2 will be produced. To find the mass in grams, use the molar mass of MgCl2:

2.00 mol MgCl2 × (95.211 g MgCl2/1 mol MgCl2)

= 190. g MgCl2

8 0

3 years ago

A movable piston traps 0.205 moles of an ideal gas in a vertical cylinder. If the piston slides without friction in the cylinder

Mazyrski [523]

Answer : The work done on the gas will be, 418.4 J

Explanation :

First we have to calculate the volume at 270°C.

$PV_1=nRT$

where,

P = pressure of gas = 1 atm

$V_1$ = volume of gas = ?

T = temperature of gas = $270^oC=273+270=543K$

n = number of moles of gas = 0.205 mol

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

$(1atm)\times V_1=0.205mol\times 0.0821L.atm/mol.K\times 543K$

$V_1=9.12L$

Now we have to calculate the volume at 24°C.

$PV_2=nRT$

where,

P = pressure of gas = 1 atm

$V_2$ = volume of gas = ?

T = temperature of gas = $24^oC=273+24=297K$

n = number of moles of gas = 0.205 mol

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

$(1atm)\times V_2=0.205mol\times 0.0821L.atm/mol.K\times 297K$

$V_2=4.99L$

Now we have to calculate the work done.

Formula used :

$w=-p\Delta V\\\\w=-p(V_2-V_1)$

where,

w = work done

p = pressure of the gas = 1 atm

$V_1$ = initial volume = 9.12 L

$V_2$ = final volume = 4.99 L

Now put all the given values in the above formula, we get:

$w=-p(V_2-V_1)$

$w=-(1atm)\times (4.99-9.12)L$

$w=4.13L.artm=4.13\times 101.3J=418.4J$

conversion used : (1 L.atm = 101.3 J)

Therefore, the work done on the gas will be, 418.4 J

6 0

3 years ago

Determine the number of ions produced in the dissociation of the compound listed. BaS

11Alexandr11 [23.1K]

BaS → Ba²⁺ + S²⁻
two types of ions

4 0

4 years ago

Read 2 more answers

(science)

ra1l [238]

Answer:

b. . the element symbol

6 0

3 years ago

Read 2 more answers

2C3H6O + 8O2 --> 6CO2 + 6H2O

grigory [225]

Answer: 0.45 moles of $H_2O$ will be produced from 0.15 moles of propanol.

Explanation:

The balanced chemical reaction is:

$2C_3H_6O+8O_2\rightarrow 6CO_2+6H_2O$

$C_3H_6O$ is the limiting reagent as it limits the formation of product and $O_2$ is the excess reagent.

According to stoichiometry :

2 moles of $C_3H_6O$ produces = 6 moles of $H_2O$

Thus 0.15 moles of $V$ will produce= $\frac{6}{2}\times 0.15=0.45moles$ of $H_2O$

Thus 0.45 moles of $H_2O$ will be produced from 0.15 moles of propanol.

7 0

3 years ago