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3 years ago

It is logical to conclude that water cannot dissolve vegetable oil because the oil is

Chemistry

2 answers:

marin [14]3 years ago

6 0

Answer:

The oil is insoluble with water.

Explanation:

The water and oil do not mix, they are illustrated as immiscible. The molecules of water are polar, that is, they exhibit a small positive charge at one terminal and a small negative charge at the other terminal, and they attach with each other. The molecules of oil are non-polar, and they possess no charge. Due to this, the molecules of oil are more fascinated with each other than to the molecules of water, and the molecules of water are more fascinated towards each other than to the molecules of oil.

Gekata [30.6K]3 years ago

3 0

In chemistry, there is a common note that says, "Like dissolves like".

This pertains to the concept that polar substances can dissolve only other polar substances. Also, nonpolar substances are also only able to dissolve nonpolar substances.

Polarity of the substance depends primarily on the type of bond and the difference in electronegativity.

Water is a polar substance while vegetable oil is not. From the concept presented above, it may be concluded that water will not be able to dissolve the vegetable oil and the assumption is logical.

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A sample of air is slowly passed through aqueous Sodium hydroxide and then over heater copper. Which gases are removed by this p

bagirrra123 [75]

Carbon dioxide and oxygen are removed from the air.

Explanation:

When air is passed through aqueous sodium hydroxide solution the carbon dioxide is removed from the air.

First the carbon dioxide will dissolve and react with water to form carbonic acid ( H₂CO₃) :

CO₂ + H₂O → H₂CO₃

The the carbonic acid will react with sodium hydroxide to form sodium carbonate (Na₂CO₃):

H₂CO₃ + 2 NaOH → Na₂CO₃ + 2 H₂O

After this by passing the air over heated cooper the oxygen is removed.

2 Cu + O₂ → 2 CuO

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neutralization reaction

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7 0

3 years ago

When FeC13 is ignited in an atmosphere of pure oxygen, this reaction takes place. 4FeCl3(sJ 30lgJ ~ 2F~0 (sJ 6Cl2(gJ If 3.00 mol

oksano4ka [1.4K]

Answer : The reagent present in excess and remains unreacted is, $O_2$

Solution : Given,

Moles of $FeCl_3$ = 3.00 mole

Moles of $O_2$ = 2.00 mole

Excess reagent : It is defined as the reactants not completely used up in the reaction.

Limiting reagent : It is defined as the reactants completely used up in the reaction.

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$2FeCl_3(s)+O_2(g)\rightarrow 2FeO(s)+3Cl_2(g)$

From the balanced reaction we conclude that

As, 2 moles of $FeCl_3$ react with 1 mole of $O_2$

So, 3.00 moles of $FeCl_3$ react with $\frac{3.00}{2}=1.5$ moles of $O_2$

From this we conclude that, $O_2$ is an excess reagent because the given moles are greater than the required moles and $FeCl_3$ is a limiting reagent and it limits the formation of product.

Hence, the reagent present in excess and remains unreacted is, $O_2$

4 0

3 years ago

Help me pleaseee. ty if you dooo :))

Lina20 [59]

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