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yaroslaw [1]
3 years ago
15

It is logical to conclude that water cannot dissolve vegetable oil because the oil is

Chemistry
2 answers:
marin [14]3 years ago
6 0

Answer:

The oil is insoluble with water.

Explanation:

The water and oil do not mix, they are illustrated as immiscible. The molecules of water are polar, that is, they exhibit a small positive charge at one terminal and a small negative charge at the other terminal, and they attach with each other. The molecules of oil are non-polar, and they possess no charge. Due to this, the molecules of oil are more fascinated with each other than to the molecules of water, and the molecules of water are more fascinated towards each other than to the molecules of oil.

Gekata [30.6K]3 years ago
3 0
In chemistry, there is a common note that says, "Like dissolves like".

This pertains to the concept that polar substances can dissolve only other polar substances. Also, nonpolar substances are also only able to dissolve nonpolar substances. 

Polarity of the substance depends primarily on the type of bond and the difference in electronegativity. 

Water is a polar substance while vegetable oil is not. From the concept presented above, it may be concluded that water will not be able to dissolve the vegetable oil and the assumption is logical. 
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Answer:

125.5 ×10^-3 m^3= 0.1255 m^3

Explanation:

Volume=5.6mol×22.414dm^3

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7 0
3 years ago
Calculate the maximum KE and velocity of an electron from zinc by a 275nm photon
Dmitry [639]

Answer:

Kinetic energy: 6.024*10^{-20}

Velocity: 3.64*10^{5}

Explanation:

From the equations of the photo-electric effect,

We know:

hv=hv_0+K.E

Where,

1.h is the Planck's constant which is 6.626*10^{-34}

2.v,v_0 are the frequency of light emitted and threshold frequencies respectively.

3.K.E is the kinetic energy of the electrons emitted.

By fact, we come to know that the threshold frequency of Zn is 300nm

And also v=\frac{c}{d}

Where ,

1. c is the speed of light =3*10^8

2.d is the wavelength.

Thus,

\frac{hc}{d}=\frac{hc}{d_0}+K.E\\K.E=\frac{hc}{d}-\frac{hc}{d_0}\\K.E=hc*(\frac{1}{d}-\frac{1}{d_0})\\K.E=6.626*10^{-34}*3*10^8*(\frac{1}{275*10^{-9}}-\frac{1}{300*10^{-9}})\\K.E=6.024*10^{-20}kgm^2s^{-2}

Now to find velocity:

K.E=\frac{1}{2}mv^2\\v^2=1.324*10^{11}\\v=3.64*10^5

8 0
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8 0
3 years ago
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An aqueous solution of hydrochloric acid is standardized by titration with a 0.137 M solution of sodium hydroxide. If 16.1 mL of
Andre45 [30]

The molarity of the hydrochloric acid, HCl solution given the data is 0.079 M

<h3>Balanced equation </h3>

HCl + NaOH —> NaCl + H₂O

From the balanced equation above,

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  • The mole ratio of the base, NaOH (nB) = 1

<h3>How to determine the molarity of HCl </h3>
  • Molarity of base, NaOH (Mb) = 0.137 M
  • Volume of base, NaOH (Vb) = 16.1 mL
  • Volume of acid, HCl (Va) = 27.9 mL
  • Molarity of acid, HCl (Ma) =?

MaVa / MbVb = nA / nB

(Ma × 27.9) / (0.137 × 16.1) = 1

(Ma × 27.9) / 2.2057  = 1

Cross multiply

Ma × 27.9 = 2.2057

Divide both side by 27.9

Ma = 2.2057 / 27.9

Ma = 0.079 M

Thus, the molarity of the HCl solution is 0.079 M

Learn more about titration:

brainly.com/question/14356286

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