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12345 [234]
3 years ago
14

Determine the specific heat ofmaterial if a 12g sample absorbed 48j as it was heated from 20-40

Chemistry
1 answer:
devlian [24]3 years ago
6 0

Answer:

c =0.2 J/g.°C

Explanation:

Given data:

Specific heat of material = ?

Mass of sample = 12 g

Heat absorbed = 48 J

Initial temperature = 20°C

Final temperature = 40°C

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =  40°C -20°C

ΔT =  20°C

48 J = 12 g×c×20°C

48 J =240 g.°C×c

c = 48 J/240 g.°C

c =0.2 J/g.°C

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denpristay [2]

Answer:

0.164541341 g H2

Explanation:

1) Convert grams to moles by dividing by RMM of Magnesium (24.31g).

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2) Use the balanced equation's ratio of 1 mol Mg: 1 mol H2.

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3) Convert the mol of H2 back into grams by multiplying by H2's RMM (2 g).

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* Answer can be rounded to your liking *

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<u>Explanation:</u>

The sulfuric acid is dissolved in water and it formed a solvation sphere of water molecules around the sulphur ions. So on stirring the beaker is getting warm. As the beaker is getting warm, this means the reaction occuring between sulfuric acid and water is exothermic reaction.

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Explanation :

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