I need help with this math problem it should be easy but im not good in math sooo...
2 answers:
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Answer:
(i) the other two sides are 6 and 6
(ii) the other two sides are
Step-by-step explanation:
(i) Sine: sin(θ) = Opposite ÷ Hypotenuse
Cosine: cos(θ) = Adjacent ÷ Hypotenuse
Tangent: tan(θ) = Opposite ÷ Adjacent
Here adjacent side = 6
opposite side = d
angle = 45°
other angles are 90° and 45°
tan (45) = Opposite ÷ Adjacent
1 = d ÷ 6
∴ d = 6 × 1 = 6
so opposite side = 6
Hypotenuse ² = opposite side ² + adjacent side²
= 6² + 6²
= 36 + 36
= 72
hypotenuse =
= 6
the other two sides are 6 and 6
(ii) here adjacent side = 4√3
angle = 30°
other angles are 90° and 60°
opposite side = d
tan ( 30) = opposite ÷ adjacent
= d ÷ 4√3
= d × (
)
3 d = 4
therefore d =
therefore opposite side =
Hypotenuse ² = opposite side ² + adjacent side²
=( )² +(
)²
=
therefore hypotenuse =
=
the other two sides are
