The answer should be rain water
Answer:
) Presence of specific glycoproteins on the cell membrane
Explanation:
When specif glycoproteins(antigens) or antibody are present on a cell membrane of Red blood cell,they can be used to identify the blood type.Antigens are substances capable of triggering an immune response in a cells.
In addition,they function in transport of molecules across the RBC. They help in the maintenance of the RBC,and aiding the arrest of cells capable of causing diseases to the body.
Therefore,they are good determinants of blood types,based on this two types of antigens present in a blood type.
These two antigens used for classification of blood types are the 1-the ABO antigens 2,the Rhesus antigens.
Essentially,when a WBC produces an antibody ,which is a molecule that defends the body,If this is not compatible,the antibody will recognize it as a foreign body and attack it.Thus such blood types are not compatible. Thus the antibody-antigen reaction are good for knowing and classify blood types.
Antigen can also be glycoprotein,carbohydrate or glycolipids.
Generally blood types are inherited from both parents.Therefore the antigen present on the RBC are combination of the alleles from each parent.
Answer:
The population of each bacteria in 1, 2, 3 are 12, 8, and 7 respectively.
Explanation:
From the given information:
For food source A; we have:
3P₁ + P₂ + 2P₃ = 58 units of food A ---- (1)
For food source B; we have:
2P₁ + 4P₂ + 2P₃ = 70 units of food B ---- (2)
For food source C; we have:
P₁ + P₂ = 20 units of food C ----- (3)
From equation (1) and (2); we have:
3P₁ + P₂ + 2P₃ = 58
2P₁ + 4P₂ + 2P₃ = 70
By elimination method
3P₁ + P₂ + 2P₃ = 58
-
2P₁ + 4P₂ + 2P₃ = 70
<u> </u>
<u> P₁ - 3P₂ + 0 = - 12 </u>
P₁ = -12 + 3P₂ ---- (4)
Replace, the value of P₁ in (4) into equation (3)
P₁ + P₂ = 20
-12 + 3P₂ + P₂ = 20
4P₂ = 20 + 12
4P₂ = 32
P₂ = 32/4
P₂ = 8
From equation (3) again;
P₁ + P₂ = 20
P₁ + 8 = 20
P₁ = 20 - 8
P₁ = 12
To find P₃; replace the value of P₁ and P₂ into (1)
3P₁ + P₂ + 2P₃ = 58
3(12) + 8 + 2P₃ = 58
36 + 8 + 2P₃ = 58
2P₃ = 58 - 36 -8
2P₃ = 14
P₃ = 14/2
P₃ = 7
Thus, the population of each bacteria in 1, 2, 3 are 12, 8, and 7 respectively.
Answer:
Snapper population is decreasing
Explanation:
The population is decreasing since the human population is increasing dramatically. As the human population increases, the demand for fish and seafood also increases since humans eat seafood and fish. As the demand for fish increases, fishermen fish for these snappers more often and in bigger loads. Snappers cant reproduce faster than these fishermen are hunting for them and so the population decreases
