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Serga [27]
3 years ago
13

Someone please help me

Mathematics
1 answer:
Elza [17]3 years ago
5 0

Answer:

student G is in the band

and student B plays the piano and is in the band

B is in the overlap of the two circles which means they fall into both categories

Hope this helped

I messed up before and did students A and B but I fixed it, so sorry that's my bad.

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Suppose I have an urn with 9 balls: 4 green, 3 yellow and 2 white ones. I draw a ball from the urn repeatedly with replacement.
Mrrafil [7]

Answer:

E(X_n)=\frac{2(n-1)}{27}

E(y)=\frac{14}{9}

Step-by-step explanation:

From the question we are told that:

Sample size n=9

Number of Green g=4

Number of yellow y=4

Number of white w=4

Probability of Green Followed by yellow P(GY) ball

 P(GY)=\frac{4}{9}*\frac{3}{9}

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Generally the equations for when n is even is mathematically given by

 Probability of success P(S)=\frac{4}{27}

 Probability of Failure P(F)=\frac{27-4}{27}

 Probability of Failure P(F)=\frac{23}{27}

Therefore

 E(X_n)=\frac{n}{2}*P

 E(X_n)=\frac{n}{2}*\frac{4}{27}

 E(X_n)=\frac{2n}{27}

Generally the equations for when n is odd is mathematically given by

 \frac{n-1}{2}

 E(X_n)=\frac{n-1}{2}*\frac{4}{27}

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b)

Probability of drawing white ball

 P(w)=\frac{2}{9}

Therefore

 E(w)=\frac{1}{p}

 E(w)=\frac{1}{\frac{2}{9}}

 E(w)=\frac{9}{2}

Therefore

 E(y)=[E(w)-1]\frac{4}{9}

 E(y)=[\frac{9}{2}-1]\frac{4}{9}

 E(y)=\frac{14}{9}

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the brightness of the illumination of an object varies inversely as the square of the distance from the object to the source of
Free_Kalibri [48]
I=k/d^2

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