Answer:
![f { - 1}^{ } = \frac{x}{4}](https://tex.z-dn.net/?f=f%20%7B%20-%201%7D%5E%7B%20%7D%20%20%3D%20%20%5Cfrac%7Bx%7D%7B4%7D%20)
Step-by-step explanation:
fjhjthfdvhfjrhgehdhrjfhdrhjthr
Answer: z = ![\sqrt{10}](https://tex.z-dn.net/?f=%5Csqrt%7B10%7D)
Step-by-step explanation:
To find <em>z</em>, you must set up a proportion to solve.
To find the altitude of a special right triangle, the formula is:
![\frac{a}{x} =\frac{x}{b}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%7D%7Bx%7D%20%3D%5Cfrac%7Bx%7D%7Bb%7D)
You can use <em>5</em> as <em>a</em> and <em>2</em> as <em>b</em> to complete the proportion:
![\frac{5}{z} =\frac{z}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7Bz%7D%20%3D%5Cfrac%7Bz%7D%7B2%7D)
Next, to solve:
<u>Step 1</u>: Cross-multiply.
![\frac{5}{z} =\frac{z}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7Bz%7D%20%3D%5Cfrac%7Bz%7D%7B2%7D)
(5)*(2) = z*z
10 = z²
<u>Step 2</u>: Take square root.
10 = z²
√10 = z
I hope this helps!
To solve this problem you must apply the proccedure shown below:
1. You have the following equation of a parabola, given in the problem above:
x<span>=1/16y^2
2. Then, based on the graph attached, you have:
p=y^2/4x
p=8^2/(4)(4)
p=64/16
p=4
3. The directrix is:
directrix=h-p
directrix=0-4
directrix=-4
The answer is:-4</span>