The answer can be explained when you burn something cleanly (with a very hot item) or not. With a candle lots of Carbon dioxide is producted but when using a bunson burner hardly any CO2 is produced.
Answer:
A. for K>>1 you can say that the reaction is nearly irreversible so the forward direction is favored. (Products formation)
B. When the temperature rises the equilibrium is going to change but to know how is going to change you have to take into account the kind of reaction. For endothermic reactions (the reverse reaction is favored) and for exothermic reactions (the forward reaction is favored)
Explanation:
A. The equilibrium constant K is defined as

In any case
aA +Bb equilibrium Cd +dD
where K is:
![K= \frac{[C]^{c}[D]^{d}}{[A]^{a}[B]^{b}}](https://tex.z-dn.net/?f=K%3D%20%5Cfrac%7B%5BC%5D%5E%7Bc%7D%5BD%5D%5E%7Bd%7D%7D%7B%5BA%5D%5E%7Ba%7D%5BB%5D%5E%7Bb%7D%7D)
[] is molar concentration.
If K>>> 1 it means that the molar concentration of products is a lot bigger that the molar concentration of reagents, so the forward reaction is favored.
B. The relation between K and temperature is given by the Van't Hoff equation

Where: H is reaction enthalpy, R is the gas constant and T temperature.
Clearing the equation for
we get:

Here we can study two cases: when delta
is positive (exothermic reactions) and when is negative (endothermic reactions)
For exothermic reactions when we increase the temperature the denominator in the equation would have a negative exponent so
is greater that
and the forward reaction is favored.
When we have an endothermic reaction we will have a positive exponent so
will be less than
the forward reactions is not favored.

Erosion weathering decomposition one of those
Looking at this equation P= (pa*pb)/ (pa+(pb-pa)) ya where pa=vap press a and ya= vap composition a and P= total pressure,it relates vapor pressure mixture to vapor composition. This is derived using the combination of Dalton's and Raoult's laws.
Answer:
CH2- CH3
|
CH3 - CH2 - C - CH - CH2 - CH2 - CH3
| |
CH3 CH3
Explanation:
Heptane
CH3 - CH2 - CH2 - CH2 - CH2 - CH2 - CH3
3 ethyl 3, 4 dimethylheptane
CH2- CH3
|
CH3 - CH2 - C - CH - CH2 - CH2 - CH3
| |
CH3 CH3