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3 years ago

Help here are the choices

Chemistry

2 answers:

Murljashka [212]3 years ago

5 0

PH Answer/definition - A value from 0 to 14 that is used to specify how acidic or basically a compound of when it is dissolved in water.

Ions Answer/definition - An atom or molecule that has a positive of negative charge.

Acid Answer/definition - A compound that increases the hydroxide ions (OH-) when it is dissolved in a solution. (Arrhenius Acid)

Base Answer/definition - A compound that increases hydrogen ions (H+) when it is dissolved in a solution.

Hope this helps you out :)))

Svetach [21]3 years ago

5 0

The first option is an Ion.
The second option js Base.
The third option is pH.
The last option is Acid.

Brainliest please!!

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All scientific ___________ must be based on careful and rational examinations of the facts.

ipn [44]

I think you forgot to give the options along with the question. I am answering the question based on my knowledge and research.All scientific theories must be based on careful and rational examinations of the facts. I hope that this is the answer that you were looking for and it has actually come to your help.

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4 years ago

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Given the amount of camphor (200mg) we are using in this experiment, please determine how many mg of sodium borohydride to use i

swat32

Answer:

Explanation:

From the given information:

Camphor may be reduced as readily in the presence of sodium borohydride(NaHB4). The resulting compound which is stereoselective requires 1 mole of sodium borohydride (NaHB4) to reduce 1 mole of camphor in this reaction. The reaction is shown below.

Through the reduction process of camphor, the reducing agent can reach the carbonyl face with a one-carbon linkage. The product stereoisomer is known as borneol.

If the molecular weight of camphor = 152.24 g/mol

and it mass = 200 mg

The its no of moles = 200 mg/ 152.24 g/mol

= 1.3137 mmol

Now the amount of the required mmol for NaBH4 to be consumed in the reaction = 5.2 × 1.3137 mmol

= 6.831 mmol

since the molar mass of NaBH4 = 37.83 g/mol

Then, using the same formula:

No of moles = mass/molar mass

mass = No of moles × molar mass

mass = 6.831 mmol × 37.83 g/mol

mass of NaBH4 used = 258.42 mg

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3 years ago

For which characteristic would a human MOST LIKELY selectively breed a house cat?

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4 years ago

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An unknown salt is either NaF, NaCl, or NaOCl. When 0.050 mol of the salt is dissolved in water to form 0.500 L of solution, the

victus00 [196]

Answer: The unknown salt is NaF

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles of salt = 0.050 moles

Volume of solution = 0.500 L

Putting values in above equation, we get:

$\text{Molarity of salt}=\frac{0.050mol}{0.500L}\\\\\text{Molarity of salt}=0.1M$

To calculate the hydroxide ion concentration, we first calculate pOH of the solution, which is:

pH + pOH = 14

We are given:

pH = 8.08

$pOH=14-8.08=5.92$

To calculate pOH of the solution, we use the equation:

$pOH=-\log[OH^-]$

Putting values in above equation, we get:

$5.92=-\log[OH^-]$

$[OH^-]=10^{-5.92}=1.202\times 10^{-6}M$

The unknown salt given are formed by the combination of weak acid and strong acid which is NaOH

The chemical equation for the hydrolysis of $X^-$ ions follows:

$X^-(aq.)+H_2O(l)\rightleftharpoons HX(aq.)+OH^-(aq.);K_b$

Initial: 0.1

At eqllm: 0.1-x x x

Concentration of $OH^-=x=1.202\times 10^{-6}M$

The expression of $K_b$ for above equation follows:

$K_b=\frac{[OH^-][HX]}{[X^-]}$

Putting values in above expression, we get:

$K_b=\frac{(1.202\times 10^{-6})\times (1.202\times 10^{-6})}{(1-(1.202\times 10^{-6}))}\\\\K_b=1.445\times 10^{-11}M$

To calculate the acid dissociation constant for the given base dissociation constant, we use the equation:

$K_w=K_b\times K_a$

where,

$K_w$ = Ionic product of water = $10^{-14}$

$K_a$ = Acid dissociation constant

$K_b$ = Base dissociation constant = $1.445\times 10^{-11}$

Putting values in above equation, we get:

$10^{-14}=1.445\times 10^{-11}\times K_a\\\\K_a=\frac{10^{-14}}{1.445\times 10^{-11}}=6.92\times 10^{-4}$

We know that:

$K_a\text{ for HF}=6.8\times 10^{-6}$

$K_a\text{ for HCl}=1.3\times 10^{6}$

$K_a\text{ for HClO}=3.0\times 10^{-8}$

So, the calculated $K_a$ is approximately equal to the $K_a$ of HF

Hence, the unknown salt is NaF

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3 years ago

Balance the equation for magnasuin and oxygen to yield magnasuimoxide

Minchanka [31]

Answer:

2Mg + O₂ → 2MgO

Explanation:

Chemical equation:

Mg + O₂ → MgO

Balanced chemical equation:

2Mg + O₂ → 2MgO

The balanced equation s given above and it completely follow the law of conservation of mass.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by french chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

Steps to balanced the equation:

Step 1:

Mg + O₂ → MgO

Mg = 1 Mg = 1

O = 2 O = 1

Step 2:

2Mg + O₂ → MgO

Mg = 2 Mg = 1

O = 2 O = 1

Step 3:

2Mg + O₂ → 2MgO

Mg = 2 Mg = 2

O = 2 O = 2

6 0

3 years ago