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Feliz [49]
4 years ago
5

What is 8/6 divided by 5/4?

Mathematics
2 answers:
34kurt4 years ago
7 0

Answer:

1 \frac{1}{15}

Step-by-step explanation:

<em>Hey there!</em>

<em />

Well when dividing fractions you need to use Keep, Change, Flip.

\frac{8}{6} / \frac{5}{4}

Keep, Change, Flip

\frac{8}{6} * \frac{4}{5}

\frac{32}{30}

Simplified

16/15

1 \frac{1}{15}

<em>Hope this helps :)</em>

Irina18 [472]4 years ago
4 0

Answer:

The answer is 16/15 or 1 1/15.

Step-by-step explanation:

First, you have to multiply it by converting the second fraction upside down:

\frac{8}{6}  \div  \frac{5}{4}

=  \frac{8}{6}  \times  \frac{4}{5}

Next, you have to cut out the common terms and multiply all:

\frac{8}{6}  \times  \frac{4}{5}

=  \frac{8}{3}  \times  \frac{2}{5}

=  \frac{16}{15}  \:  \: or \: \:  1 \frac{1}{15}

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Hello! How do I find the surface area of this prism? Thanks!
Studentka2010 [4]
Answer: Choice C) 124 square cm

------------------------------------------------------------------

Explanation:

Let's calculate the area of the trapezoid shown
b1 and b2 are the parallel bases; h is the height of the 2D trapezoid
b1 = 2
b2 = 5
h = 1.5

A = h*(b1+b2)/2
A = 1.5*(2+5)/2
A = 1.5*7/2
A = 10.5/2
A = 5.25
The area of one 2D trapezoid is 5.25 sq cm
There are two of these trapezoids that form the base faces of the trapezoidal prism. So the total base area is 2*5.25 = 10.5 sq cm
Keep this value (10.5) in mind. We'll use it later.

------------

Now onto the lateral surface area (LSA)
It turns out that the formula for the LSA is
LSA = p*d
where 
p = perimeter of the trapezoid shown
d = depth or height of the 3D trapezoid (I'm not using h as it was used earlier)
This formula works for any polygonal base. It doesn't have to be a trapezoid.

In this case the perimeter is,
p = 1.7+2+2.65+5
p = 11.35

So
LSA = p*d
LSA = 11.35*10
LSA = 113.5

Add this LSA to the base area found earlier
10.5+113.5 = 124

The total surface area is 124 square cm
8 0
4 years ago
Please someone help me to prove this. ​
morpeh [17]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Use the Double Angle Identity: sin 2Ф = 2sinФ · cosФ

Use the Sum/Difference Identities:

sin(α + β) = sinα · cosβ + cosα · sinβ

cos(α - β) = cosα · cosβ + sinα · sinβ

Use the Unit circle to evaluate: sin45 = cos45 = √2/2

Use the Double Angle Identities:   sin2Ф = 2sinФ · cosФ

Use the Pythagorean Identity: cos²Ф + sin²Ф = 1

<u />

<u>Proof LHS → RHS</u>

LHS:                                  2sin(45 + 2A) · cos(45 - 2A)

Sum/Difference: 2 (sin45·cos2A + cos45·sin2A) (cos45·cos2A + sin45·sin2A)

Unit Circle:    2[(√2/2)cos2A + (√2/2)sin2A][(√2/2)cos2A +(√2/2)·sin2A)]  

Expand:        2[(1/2)cos²2A  + cos2A·sin2A + (1/2)sin²2A]

Distribute:              cos²2A   + 2cos2A·sin2A + sin²2A  

Pythagorean Identity:    1 + 2cos2A·sin2A

Double Angle:                1 + sin4A

LHS = RHS:  1 + sin4A = 1 + sin4A   \checkmark

6 0
3 years ago
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