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Aleonysh [2.5K]
3 years ago
15

Please explain the steps to answer part A

Mathematics
1 answer:
kozerog [31]3 years ago
6 0
First you have to make all the units the same: so convert all the ounces to pounds, then add up all the pounds and that is the weight of the books.
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I know how to do it I'm just lazy
alexandr402 [8]
Jason = 142 cm = 1.42 m
Amy = 137 cm = 1.37 m
Joseph = 1397 mm = 1.397 m

From shortest to tallest

I) Amy, Joseph, Jason
8 0
3 years ago
Simplify u^2+3u/u^2-9<br> A.u/u-3, =/ -3, and u=/3<br> B. u/u-3, u=/-3
VashaNatasha [74]
  The correct answer is:  Answer choice:  [A]:
__________________________________________________________
→  "\frac{u}{u-3} " ;  " { u \neq ± 3 } " ; 

          →  or, write as:  " u / (u − 3) " ;  {" u ≠ 3 "}  AND:  {" u ≠ -3 "} ; 
__________________________________________________________
Explanation:
__________________________________________________________
 We are asked to simplify:
  
  \frac{(u^2+3u)}{(u^2-9)} ;  


Note that the "numerator" —which is:  "(u² + 3u)" — can be factored into:
                                                      →  " u(u + 3) " ;

And that the "denominator" —which is:  "(u² − 9)" — can be factored into:
                                                      →   "(u − 3) (u + 3)" ;
___________________________________________________________
Let us rewrite as:
___________________________________________________________

→    \frac{u(u+3)}{(u-3)(u+3)}  ;

___________________________________________________________

→  We can simplify by "canceling out" BOTH the "(u + 3)" values; in BOTH the "numerator" AND the "denominator" ;  since:

" \frac{(u+3)}{(u+3)} = 1 "  ;

→  And we have:
_________________________________________________________

→  " \frac{u}{u-3} " ;   that is:  " u / (u − 3) " ;  { u\neq 3 } .
                                                                                and:  { u\neq-3 } .

→ which is:  "Answer choice:  [A] " .
_________________________________________________________

NOTE:  The "denominator" cannot equal "0" ; since one cannot "divide by "0" ; 

and if the denominator is "(u − 3)" ;  the denominator equals "0" when "u = -3" ;  as such:

"u\neq3" ; 

→ Note:  To solve:  "u + 3 = 0" ; 

 Subtract "3" from each side of the equation; 

                       →  " u + 3 − 3 = 0 − 3 " ; 

                       → u =  -3 (when the "denominator" equals "0") ; 
 
                       → As such:  " u \neq -3 " ; 

Furthermore, consider the initial (unsimplified) given expression:

→  \frac{(u^2+3u)}{(u^2-9)} ;  

Note:  The denominator is:  "(u²  − 9)" . 

The "denominator" cannot be "0" ; because one cannot "divide" by "0" ; 

As such, solve for values of "u" when the "denominator" equals "0" ; that is:
_______________________________________________________ 

→  " u² − 9 = 0 " ; 

 →  Add "9" to each side of the equation ; 

 →  u² − 9 + 9 = 0 + 9 ; 

 →  u² = 9 ; 

Take the square root of each side of the equation; 
 to isolate "u" on one side of the equation; & to solve for ALL VALUES of "u" ; 

→ √(u²) = √9 ; 

→ | u | = 3 ; 

→  " u = 3" ; AND;  "u = -3 " ; 

We already have:  "u = -3" (a value at which the "denominator equals "0") ; 

We now have "u = 3" ; as a value at which the "denominator equals "0"); 

→ As such: " u\neq 3" ; "u \neq -3 " ;  

or, write as:  " { u \neq ± 3 } " .

_________________________________________________________
6 0
3 years ago
PLEASE HELP!!!! I will mark brainliest
strojnjashka [21]

Answer:

I think B.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
To cover a rectangular region of her yard, Penny needs at least 155 square feet of sod. The length of the
Tasya [4]

<u><em>To cover a rectangular region of her yard, Penny needs at least 170.5 square feet of sod. The length of the region is 15.5 feet. What are the possible widths of the region?</em></u>

<u><em></em></u>

<u><em>L=length=15.5 ft; W=width; A=area=>170.5 sq ft</em></u>

<u><em></em></u>

<u><em>L*W=>170.5 sq ft Divide each side by L</em></u>

<u><em></em></u>

<u><em></em></u>

<u><em>W=>170.5 sq ft/L</em></u>

<u><em></em></u>

<u><em>W=>170.5 sq ft/15.5 ft=>11 feet</em></u>

<u><em></em></u>

ANSWER: To cover at least 170.5 sq ft. the width must be at least 11 feet.

<h2><em><u>Brainly pls</u></em></h2>

5 0
3 years ago
Answer if you do know
Alex777 [14]

Answer:

Find the hypotenuse:

3^3 + 10^2 = 109

Square root of 109 is around 10.4

8 0
3 years ago
Read 2 more answers
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