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zzz [600]
2 years ago
12

Determine the discount between the point(-4,2) and the line 4y=3×+6​

Mathematics
1 answer:
frozen [14]2 years ago
6 0

Answer:

d = 14/5

Step-by-step explanation:

The point (-4,2) means that;

At x = -4, y = 2

Now general form of a linear equation is;

Ax + By + C = 0

We are given;

4y = 3x + 6​

Rearranging to the form of a linear equation gives;

3x - 4y + 6 = 0

Thus, A = 3, B = -4 and C = 6

Thus, at point (-4,2), distance between them is;

d = (3(-4) - 4(2) + 6)/√(3² + (-4)²)

d = -14/5

We will take the absolute value.

Thus; d = 14/5

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3 years ago
Write the equation of the line with an x-intercept at (0,2) and perpendicular to 3x+4y=12.
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