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zzz [600]
2 years ago
12

Determine the discount between the point(-4,2) and the line 4y=3×+6​

Mathematics
1 answer:
frozen [14]2 years ago
6 0

Answer:

d = 14/5

Step-by-step explanation:

The point (-4,2) means that;

At x = -4, y = 2

Now general form of a linear equation is;

Ax + By + C = 0

We are given;

4y = 3x + 6​

Rearranging to the form of a linear equation gives;

3x - 4y + 6 = 0

Thus, A = 3, B = -4 and C = 6

Thus, at point (-4,2), distance between them is;

d = (3(-4) - 4(2) + 6)/√(3² + (-4)²)

d = -14/5

We will take the absolute value.

Thus; d = 14/5

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3 years ago
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240 × 84.85  = 10182

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We will need the measure of angle A, then use the sine of A to get the height of the line from angle C perpendicular to the base, side b.

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sin(50.47) = 0.77129

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Using rounded values here to calculate Area :

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2 years ago
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nasty-shy [4]
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2 years ago
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