Question

What equation gives the position at a specific time for an object with constant acceleration? a. x=x0+v0t+1/2}at^2b. x=v0t+at^2c. vf=v0+atd. v^2f=v0^2+2aΔx

Answer 1

The first option is mathematically described as

$x = x_0 +v_0 t +\frac{1}{2} at^2$

Here,

$x_0 =$Initial position

$v_0 =$ Initial velocity

t = Time

a = Acceleration

As we can see in this equation, the position of a body is described taking into account its initial point with respect to the reference system, the initial velocity of this body and the acceleration when it is constant. All this depending on time.

The second option despises the initial position, so it does not allow the exact calculation of the position.

The third option does not consider the position, only the speed and acceleration with respect to time

The fourth option considers acceleration and distance but does not take into account the time of the object.

Therefore the correct answer is A.