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lorasvet [3.4K]
3 years ago
15

What equation gives the position at a specific time for an object with constant acceleration? a. x=x0+v0t+1/2}at^2b. x=v0t+at^2c

. vf=v0+atd. v^2f=v0^2+2aΔx
Physics
1 answer:
Ostrovityanka [42]3 years ago
6 0

The first option is mathematically described as

x = x_0 +v_0 t +\frac{1}{2} at^2

Here,

x_0 =Initial position

v_0 = Initial velocity

t = Time

a = Acceleration

As we can see in this equation, the position of a body is described taking into account its initial point with respect to the reference system, the initial velocity of this body and the acceleration when it is constant. All this depending on time.

The second option despises the initial position, so it does not allow the exact calculation of the position.

The third option does not consider the position, only the speed and acceleration with respect to time

The fourth option considers acceleration and distance but does not take into account the time of the object.

Therefore the correct answer is A.

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when a temparature of a coin is 75°C, the coin's diameter increases. if the original diameter of a coin is 1.8*10^-2 m and its c
andrey2020 [161]

Answer:

ΔD = 2.29 10⁻⁵ m

Explanation:

This is a problem of thermal expansion, if the temperature changes are not very large we can use the relation

          ΔA = 2α A ΔT

the area is

         A = π r² = π D² / 4

we substitute

         ΔA = 2α π D² ΔT/4

as they do not indicate the initial temperature, we assume that ΔT = 75ºC

    α = 1.7 10⁻⁵ ºC⁻¹

we calculate

          ΔA = 2 1.7 10⁻⁵ pi (1.8 10⁻²) ² 75/4

          ΔA = 6.49 10⁻⁷ m²

by definition

           ΔA = A_f- A₀

           A_f = ΔA + A₀

           A_f = 6.49 10⁻⁷ + π (1.8 10⁻²)² / 4

           A_f = 6.49 10⁻⁷ + 2.544 10⁻⁴

           A_f = 2,551 10⁻⁴ m²

the area is

           A_f = π D_f² / 4

           A_f = \sqrt{4  A_f /\pi }

           D_f = \sqrt{4 \ 2.551 10^{-4} /\pi }

           D_f = 1.80229 10⁻² m

the change in diameter is

           ΔD = D_f - D₀

           ΔD = (1.80229 - 1.8) 10⁻² m

           ΔD = 0.00229 10⁻² m

           ΔD = 2.29 10⁻⁵ m

5 0
3 years ago
You've probably seen how the surface of a tire can partially melt and leave a mark on the road when a car's brakes are applied r
yan [13]

Answer:

tire marks are due to the increase in thermal energy

Explanation:

When a tire is spinning at a given speed when the brakes are applied hard, the friction between the tire's particulate and the ground surface is high enough that some tire particles are transferred to the ground.

This is reflected in the heat transfer from the tire to the ground.

Consequently, tire marks are due to the increase in thermal energy and the change in the friction force of the tire.

7 0
3 years ago
What types of ions will sodium and chlorine each form? Explain
vaieri [72.5K]

Answer:

The sodium forms cations and chlorine forms anions.

Explanation:

  1. During the formation of the bonding, the sodium atom loses one electron and forms a positively charged ion called cation.
  2. The chlorine atom receives one electron and forms a negatively charged ion called anion.
  3. The electro-negativity of the atom determines the bonding nature of the atoms.
  4. In case of sodium and chlorine, it forms the ionic bonding where there is a transfer of an electron from one atom to the other.
  5. Hence the charge is given by Na⁺ and Cl⁻
8 0
4 years ago
What makes comets different from asteroids and meteoroids? Question 8 options: A.They don't consist of ice. B.They travel in spa
Rus_ich [418]

Answer:

(C) They consist of ice.

Explanation:

Comet consist of a body of ice, rock and dust that can be several miles in diameter and orbits the sun. Debris from comets is the main source of many meteoroids.

8 0
3 years ago
The root-mean-square speed (thermal speed) of the molecules of a gas is 200m/s at 23.0°C. At 227°C the root-mean-square speed (t
777dan777 [17]

Answer:

330 m/s  approx

Explanation:

The RMS speed of a gas is proportional to square root of its absolute temperature is

V ( RMS ) ∝ √T

\frac{V_1}{V_2} =\sqrt{\frac{T_1}{T_2} }

Here V₁ = 200 , T₁ = 23 +273 = 300K , T₂ = 227 +273 = 500 K

Putting the values

200 / V₂ = \sqrt{\frac{300}{500} }

V₂ = 330 m/s  approx

8 0
4 years ago
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