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Aleksandr [31]
3 years ago
13

Which atom is most likely to form a metallic bond ?

Physics
1 answer:
Nana76 [90]3 years ago
5 0

<u>Answer:</u>

"Aluminium (Al)" atom is most likely to form a metallic bond.

<u>Explanation:</u>

A kind of chemical bonding which generates between conduction electrons and positively charged metal ions from the attractive electrostatic force is understood as "metallic bonding". It may be defined as sharing free electrons among a positively charged ion structure.

A sheet of foil made from aluminum is constructed from metal bonds. Metallic relations are formed by strong forces of attraction. This property leads to low volatility, high melting and boiling points, and most metals are high density.

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it would be letter E. near oceanic ridges

Explanation:

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How many states of matter do you think are in the photo? Describe at least two.
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Three, the liquid in the man's cup, the stove is solid, and the air around them is a gas

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4 years ago
A uniform magnetic field passes through a horizontal circular wire loop at an angle 19.5 ∘ from the vertical. The magnitude of t
nlexa [21]

To solve this problem, we will apply the concepts related to Faraday's law that describes the behavior of the emf induced in the loop. Remember that this can be expressed as the product between the number of loops and the variation of the magnetic flux per unit of time. At the same time the magnetic flux through a loop of cross sectional area is,

\Phi = BA Cos \theta

Here,

\theta = Angle between areal vector and magnetic field direction.

According to Faraday's law, induced emf in the loop is,

\epsilon= -N \frac{d\Phi }{dt}

\epsilon = -N \frac{(BAcos\theta)}{dt}

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\epsilon = -N\pi r^2 cos\theta \frac{d}{dt} ( ( 3.75 T ) + ( 3.05T/s ) t + ( -6.95 T/s^2 ) t^2)

\epsilon = -N\pi r^2 cos\theta( (3.05T/s)-(13.9T/s)t )

At time t = 5.71s,  Induced emf is,

\epsilon = -(1) \pi (0.220m)^2 cos(19.5\°)(  (3.05T/s)-(13.9T/s)(5.71s))

\epsilon = 10.9V

Therefore the magnitude of the induced emf is 10.9V

4 0
3 years ago
Read 2 more answers
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- The frequency of oscillation does not depend on the amplitude.

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