Three runners run along a 1.5 mile trail one Saturday morning. The graph shows the runners’ locations starting at 9:00 a.m.
2 answers:
Answers:
The graph is attached below. With this information we have to answer the questions:
1) Who is at the trail start at 9:00 a.m.?
Andy
According to the graph, at 9:00 a.m. Andy is at the point (0,0), which is the begining of the trail. Hence, he is at the trail start.
2) Who runs fastest?
Bertha
If we observe the slopes of each line; Bertha's slope has the least steep. This means she is displacing more in less time, than the other two runners.
3) When do Andy and Berta cross paths?
After 8 minutes, on mile 1.
According to the graph, exactly at the point (8,1), which is at 9:08 a.m. and in mile 1; is when the paths of both runners intercept each other.
4) Who is closest to the 1.5 mile mark after 6 minutes?
Bertha
As we see in the graph, at 9:06 a.m Bertha is closest to the 1.5 mile mark, since her line is closest to this point at that time.
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1, 3, 5, 7, 9 ......
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skip one, another, skip one, another and so on
so, from 1 to 3, is 1 + 2 =3
5 is 3 +2
7 is 5+2
and so on
let us pick an odd integer, hmmm say "a"
to find the next odd one, it'd be "a + 2" of course :)
we know their sum is 316
so
once you found "a", the next one is, well, "a + 2" :)
notice, there are consecutive odd integers, every other number
skip one, another, skip one, another and so on
so, from 1 to 3, is 1 + 2 =3
5 is 3 +2
7 is 5+2
and so on
let us pick an odd integer, hmmm say "a"
to find the next odd one, it'd be "a + 2" of course :)
we know their sum is 316
so
once you found "a", the next one is, well, "a + 2" :)
Answer: The correct answer is
Step-by-step explanation:
To find a quotient, we need to divide the two numbers. The equation given to us is :
To Simplify the above equation and finding out the quotient, we need to divide the above equation, we get:
Taking the reciprocal of the denominator and multiplying it with the numerator, we get:
Hence, the correct answer is