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astraxan [27]
3 years ago
11

Josiah kept track of how many songs of each genre were played in an hour from his MP3 player. The counts are displayed in the ta

ble below. He has a total of 1,500 songs on his player. Josiah predicted the number of rock songs on his MP3 player to be 300 songs. Which statements about his solution are true? Select three choices.
Mathematics
1 answer:
viktelen [127]3 years ago
5 0
What table what 3 three choices?
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The thickness of each type of coin is shown in the table. How much thicker is stack of dollars worth of nickels than a dollars w
Lilit [14]
Let our basis be worth 1 dollar. A nickel's worth is $0.05. In order to come up with $1, the number of nickels should be:

Number of nickels = $1 * 1 nickel/$0.05 = 20 nickels
Thickness of 20 nickels = 20 nickels * 1.95 mm = 39 mm

Let's do the same for the quarters. Each quarter is worth $0.25.

Number of quarters = $1 * 1 quarter/$0.25 = 4 quarters
Thickness of 4 quarters = 4 quarters * 1.75 mm = 7 mm

Find the ratio of the two:
39 mm/7 mm = 5.57

Therefore, a stack of nickels is 5.57 times thicker than a stack of quarters worth one dollar.
7 0
4 years ago
What is the GCF of 61 & 73
oee [108]
Turns out that both of these numbers are PRIME! Neither of them can be divided down with the same number or different. Hope this helps!
6 0
3 years ago
Read 2 more answers
IXL 6th grade FF.1
maksim [4K]

Answer:

p=5

Step-by-step explanation:

if 5+3 = 8

13-8=5

and both sides of the triangle need to be the same

6 0
3 years ago
Read 2 more answers
Which polynomial is prime? x3 + 3x2 – 2x – 6 x3 – 2x2 + 3x – 6 4x4 + 4x3 – 2x – 2 2x4 + x3 – x + 2
alexandr1967 [171]
D. 2x4+x3–x+2 <span>is prime</span>
4 0
3 years ago
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A school is planning to construct two rectangular play areas in the playground. The length of play area A must be 1 foot longer
Anna11 [10]

Answer:

А.The system has two solutions, but only one is viable because the other results in a negative width.

Step-by-step explanation:

Given

Let:

L_A \to length of play area A

W_A \to width of play area A

L_B \to length of play area B

W_B \to width of play area B

x \to Area of A

y \to Area of B

From the question, we have the following:

L_A = 1 + 4W_A

W_B = 2 + W_A

L_B = 2 + 3W_B

x = y

The area of A is:

x = L_A * W_A

This gives:

x = (1 + 4W_A) * W_A

Open bracket

x = W_A + 4W_A^2

The area of B is:

y = L_B * W_B

y = (2 + 3W_B) * ( 2 + W_A)

Substitute: W_B = 2 + W_A

y = (2 + 3(2 + W_A)) * ( 2 + W_A)

Open brackets

y = (2 + 6 + 3W_A) * ( 2 + W_A)

y = (8 + 3W_A) * ( 2 + W_A)

Expand

y = 16 + 8W_A + 6W_A + 3W_A^2

y = 16 + 14W_A + 3W_A^2

We have that:

x = y

This gives:

W_A + 4W_A^2 = 16 + 14W_A + 3W_A^2

Collect like terms

4W_A^2 - 3W_A^2 + W_A  -14W_A  - 16 =0

W_A^2  -13W_A  - 16 =0

Using quadratic calculator, we have:

W_A = -14.1 or W = 1.13 --- approximated

But the width can not be negative; So:

W = 1.19

7 0
3 years ago
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