The given question is incomplete as the genotype of the parents is not given, so the answer is providing in the followings case:
1. dominant parent and recessive parent
2. heterozygous parents
Answer:
1. dominant parent and recessive parent:
dominant parents can be represented by LL and recessive parent is represented by ll, so the gametes would be L, L and l, l.
so,
L L
l Ll Ll
l Ll Ll
so there are all offspring in heterozygous condition as we known one or two dominant allele masks the recessive allele for the trait so 100% offspring can fold their tongue.
2. heterozygous parents
In this case, parents have Ll genotype and gametes would be L and l for each parent so,
L l
L LL Ll
l Ll ll
In this case, one is pure dominant and two heterozygous whereas only one is recessive so, the phenotype of offspring that cant fol the tongue would be:
3/4 = 75%
Answer:
Here the fucose is linked to galactose by alpha1,2 glycosidic linkage.
Explanation:
Fucose is a deoxy sugar consist of 6 carbon atoms which means fucose is a hexose sugar.
Fucose does not contain -OH group at C6 carbon that"s why it is termed as deoxy sugar.
Fucose can link to both Nactylglucosame by alpha-1,6 glycosidic linkage and to galactose by alpha-1, glycosidic linkage generates the H antigen.
As donor is blood type B that means fucose is linked to galactoseof H antigen by alpha 1,2glycisidic linkage.
The answers are: BB Bb bb
The answer is C. Although the F1<span> generation will all show the dominant trait, the offspring will all be heterozygous and increase chances of future variation. </span>
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