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3 years ago

Solve the following equation for q. 8q + 4p + 4 = 4q – 8.

Mathematics

1 answer:

marishachu [46]3 years ago

4 0

Answer:

a. q= -p - 3

Step-by-step explanation:

8q+ 4p + 4= 4q - 8

8q (- 8q) + 4p + 4 = 4q (-8q) -8

4p +4 = -4q -8

4p + 4 (+8) = -4q -8 (+8)

4p + 12 = -4q

(4p + 12)/-4 = (-4q)/-4

-p -3 = q

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I need help asap pls and thank you ;)

olga55 [171]

Answer:

$\text{Length of AB is }\frac{ah}{a+h}$

Step-by-step explanation:

Given △KMN, ABCD is a square where KN=a, MP⊥KN, MP=h.

we have to find the length of AB.

Let the side of square i.e AB is x units.

As ADCB is a square ⇒ ∠CDN=90°⇒∠CDP=90°

⇒ CP||MP||AB

In ΔMNP and ΔCND

∠NCD=∠NMP (∵ corresponding angles)

∠NDC=∠NPM (∵ corresponding angles)

By AA similarity rule, ΔMNP~ΔCND

Also, ΔKAP~ΔKPM by similarity rule as above.

Hence, corresponding sides are in proportion

$\frac{ND}{NP}=\frac{CD}{MP} \thinspace\thinspace and\thinspace\thinspace \frac{KA}{KP}=\frac{AB}{PM} \\\\\frac{ND}{NP}=\frac{x}{h} \thinspace\thinspace and\thinspace\thinspace \frac{KA}{KP}=\frac{x}{h}\\\\\frac{NP}{ND}=\frac{h}{x} \thinspace\thinspace and\thinspace\thinspace \frac{KP}{KA}=\frac{h}{x}\\\\\frac{PD}{ND}=\frac{h}{x}-1 \thinspace\thinspace and\thinspace\thinspace \frac{AP}{KA}=\frac{h}{x}-1\\$

$KA(\frac{h}{x}-1)=AP$

$ND(\frac{h}{x}-1)=PD$

Adding above two, we get

$(KA+ND)(\frac{h}{x}-1)=(AP+PD)$

⇒ $(KN-AD)=\frac{x}{(\frac{h}{x}-1)}$

⇒ $a-x=\frac{x}{(\frac{h}{x}-1)}$

⇒ $a-x=\frac{x^2}{h-x}$

⇒ $x^2=ah-ax-xh+x^2$

⇒ $x(h+a)=ah$

⇒ $x=\frac{ah}{a+h}$

3 0

3 years ago

I have a question what is perimeter cuz I forgot what it was hi hi hi hi hi

andre [41]

Answer: Perimeter is when u add all around

Example: The perimeter of a square is 4,5,3,7

Add: 4+5+3+7 get 19

The perimeter will be 19

4 0

3 years ago

Read 2 more answers

What is the value of x? A. 2 Units B. 3 Units C. 5 Units D. 8 Units

Fudgin [204]

You need the formula for geometric mean for right triangles as it applies to the altitude. For us, that formula will be $\frac{BD}{AD}=\frac{CD}{BD}$ where BD is your altitude. The formula then, filled in accordingly, would be $\frac{10}{x}=\frac{4x}{10}$ . We cross multiply to get that $4x^2=100$ . Divide both sides by 4 to get $x^2=25$ , so x = 5. Choice C is the one you want.