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Svet_ta [14]
3 years ago
11

Solve the following equation for q. 8q + 4p + 4 = 4q – 8.

Mathematics
1 answer:
marishachu [46]3 years ago
4 0

Answer:

a. q= -p - 3

Step-by-step explanation:

8q+ 4p + 4= 4q - 8

8q (- 8q) + 4p + 4 = 4q (-8q) -8

4p +4 = -4q -8

4p + 4 (+8) = -4q -8 (+8)

4p + 12 = -4q

(4p + 12)/-4 = (-4q)/-4

-p -3 = q

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Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?
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Hello!

First of all we find the slope by dividing the difference of the y values by the difference of the x values as seen below.

\frac{-3-11}{1+3} = -\frac{14}{4} = \frac{7}{2}

The slope of our line is 7/2, or 3.5
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Now we will put the slope and a point on our line into slope intercept form and solve for b. We will use (-3,11).

11=3.5(-3)+b
11=10.5+b
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Our final equation is shown below.

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I hope this helps!


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