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Hunter-Best [27]
3 years ago
8

Which points is between points c and e

Mathematics
2 answers:
Bogdan [553]3 years ago
8 0

Answer:

I believe its B

forsale [732]3 years ago
3 0
The point is point s
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Please answer correctly while showing detailed working ​
igomit [66]

Answer:

243

Step-by-step explanation:

its all about laws of exponent

pls open the pic for ur answer

i hope it may have helped u

7 0
3 years ago
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Jonah is looking over his credit card statements from the past couple of months. Last month's balance was $95. This month, it wa
Reika [66]
To start with, 76 is 80% of 95. (76/95=0.8)
This means that we take the difference from 100% of 95 and 80% of 95, and get a 20% decrease.
6 0
3 years ago
The median number of goals scored by 7 players in a certain soccer season is 5. The range of the number of goals scored by those
OLEGan [10]
True true true true
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3 years ago
A line that has a rise of -34 and a run of 20.
aleksandr82 [10.1K]

Answer:

y=-1.7x-34

Step-by-step explanation:

An equation of a line is given y=mx+c, where m is the gradient or \frac{Rise}{Run}

The rise indicates the change in value of y (vertical change in the graph).

The run indicates the change in value of x (horizontal change in the graph).

Let point 1 of the graph be (x,y) = (0,-34) and point 2 be (x,y) = (20,0).

 m =\frac{Rise}{Run} \\  =\frac{-34}{20}\\  =-1.7

Substitute point 1 into the graph to get the constant c.

y=mx+c

-34=(-1.7)*(0)+c

c=-34

∴ The equation of the line is, y=-1.7x-34

7 0
3 years ago
HELP with these questions
zlopas [31]

<u>Step-by-step explanation:</u>

transform the parent graph of f(x) = ln x        into f(x) = - ln (x - 4)  by shifting the parent graph 4 units to the right and reflecting over the x-axis

(???, 0): 0 = - ln (x - 4)

            \frac{0}{-1} = \frac{-ln (x - 4)}{-1}

            0 = ln (x - 4)

            e^{0} = e^{ln (x - 4)}

             1 = x - 4

          <u> +4 </u>  <u>    +4 </u>

             5 = x

(5, 0)

(???, 1): 1 = - ln (x - 4)

            \frac{0}{-1} = \frac{-ln (x - 4)}{-1}

            1 = ln (x - 4)

            e^{1} = e^{ln (x - 4)}

             e = x - 4

          <u> +4 </u>   <u>    +4 </u>

         e + 4 = x

          6.72 = x

(6.72, 1)

Domain: x - 4 > 0

                <u>  +4 </u>  <u>+4  </u>

               x       > 4

(4, ∞)

Vertical asymptotes: there are no vertical asymptotes for the parent function and the transformation did not alter that

No vertical asymptotes

*************************************************************************

transform the parent graph of f(x) = 3ˣ        into f(x) = - 3ˣ⁺⁵  by shifting the parent graph 5 units to the left and reflecting over the x-axis

Domain: there is no restriction on x so domain is all real number

(-∞, ∞)

Range: there is a horizontal asymptote for the parent graph of y = 0 with range of y > 0.  the transformation is a reflection over the x-axis so the horizontal asymptote is the same (y = 0) but the range changed to y < 0.

(-∞, 0)

Y-intercept is when x = 0:

f(x) = - 3ˣ⁺⁵

      = - 3⁰⁺⁵

      = - 3⁵

      = -243

Horizontal Asymptote: y = 0  <em>(explanation above)</em>

5 0
3 years ago
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