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murzikaleks [220]

3 years ago

11

Find 'x' in the following

2 answers:

noname [10]3 years ago

8 0

First we have to find angle D

As it is a quadrilateral

$\\ \sf\longmapsto$

$\\ \sf\longmapsto 45+50+35+$

$\\ \sf\longmapsto 130+$

$\\ \sf\longmapsto$

$\\ \sf\longmapsto$

Now

$\\ \sf\longmapsto$

$\\ \sf\longmapsto x+230=360$

$\\ \sf\longmapsto x=360-230$

$\\ \sf\longmapsto x=130°$

Juli2301 [7.4K]3 years ago

6 0

Answer:

x = 130

Step-by-step explanation:

Sum of all the angle of quadrilateral = 360°

50 + 45 + 35 + ∠ADC = 360

130 + ∠ADC = 360

∠ADC = 360 - 130

∠ADC = 230

x = Reflex ∠ADC

= 360 - 230

= 130

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A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 31 ft/s. (a) A

julsineya [31]

Answer:

a) -13.9 ft/s

b) 13.9 ft/s

Step-by-step explanation:

a) The rate of his distance from the second base when he is halfway to first base can be found by differentiating the following Pythagorean theorem equation respect t:

$D^{2} = (90 - x)^{2} + 90^{2}$ (1)

$\frac{d(D^{2})}{dt} = \frac{d(90 - x)^{2} + 90^{2})}{dt}$

$2D\frac{d(D)}{dt} = \frac{d((90 - x)^{2})}{dt}$

$D\frac{d(D)}{dt} = -(90 - x) \frac{dx}{dt}$ (2)

Since:

$D = \sqrt{(90 -x)^{2} + 90^{2}}$

When x = 45 (the batter is halfway to first base), D is:

$D = \sqrt{(90 - 45)^{2} + 90^{2}} = 100. 62$

Now, by introducing D = 100.62, x = 45 and dx/dt = 31 into equation (2) we have:

$100.62 \frac{d(D)}{dt} = -(90 - 45)*31$

$\frac{d(D)}{dt} = -\frac{(90 - 45)*31}{100.62} = -13.9 ft/s$

Hence, the rate of his distance from second base decreasing when he is halfway to first base is -13.9 ft/s.

b) The rate of his distance from third base increasing at the same moment is given by differentiating the folowing Pythagorean theorem equation respect t:

$D^{2} = 90^{2} + x^{2}$

$\frac{d(D^{2})}{dt} = \frac{d(90^{2} + x^{2})}{dt}$

$D\frac{dD}{dt} = x\frac{dx}{dt}$ (3)

We have that D is:

$D = \sqrt{x^{2} + 90^{2}} = \sqrt{(45)^{2} + 90^{2}} = 100.63$

By entering x = 45, dx/dt = 31 and D = 100.63 into equation (3) we have:

$\frac{dD}{dt} = \frac{45*31}{100.63} = 13.9 ft/s$

Therefore, the rate of the batter when he is from third base increasing at the same moment is 13.9 ft/s.

I hope it helps you!

4 0

3 years ago

Read 2 more answers

What is the slope of the line that<br> contains the points (13,-2) and (3.-2)

Allushta [10]

Points are

(13,-2)
(3,-2)

$\boxed{\sf Slope(m)=\dfrac{y_2-y_1}{x_2-x_1}}$

$\\ \sf\longmapsto m=\dfrac{3-13}{-2+2}$

$\\ \sf\longmapsto m=\dfrac{-10}{0}$

$\\ \sf\longmapsto m=0$

8 0

3 years ago

There is a bag filled with 3 blue and 4 red marbles. A marble is taken at random from the bag, the colour is noted and then it i

oksano4ka [1.4K]

Answer:

Step-by-step explanation:

8 0

3 years ago

What is y/6 - 3 = -11

nadya68 [22]

Answer:

y=-48

Step-by-step explanation:

y/6-3=-11

y/6=-8

multiply 6/1 on each side

y=-48

7 0

3 years ago

Simplify . 7(8-1)+(-1) ^)2/1+2^2

kodGreya [7K]

Answer:

$\frac{50}{5} = 10$

Step-by-step explanation:

$\frac{7(8 - 1) + ( - 1 {)}^{2} }{1 + {2}^{2} }$

$\frac{7 \times 7 + ( - 1 {)}^{2} }{1 + {2}^{2} } = \frac{7 \times 7 + 1}{1 + {2}^{2} }$

$\frac{7 \times 7 + 1}{1 + 4} = \frac{49 + 1}{1 + 4} = \frac{49 + 1}{5}$

$= \frac{50}{5} = 10$

5 0

3 years ago