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2 years ago

Help me with this for geometry please

Mathematics

1 answer:

Kamila [148]2 years ago

8 0

Answer:

57 units

Step-by-step explanation:

So the step is we need to find out the scale factor

And the scale factor is 24/8 =3

So the parameter of ANG is

19×3

=57

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What is the standard form of nine million, twenty thousand, twenty-nine

KatRina [158]

Answer:

9000000+20000+20+9

Step-by-step explanation:

4 0

2 years ago

Sec squared 55 - tan squared 55

sergejj [24]

<u>Answer: </u>

sec squared 55 – tan squared 55 = 1

<u>Explanation:</u>

Given, sec square 55 – tan squared 55

We know that,

$\sec \Theta=\frac{\text {hypotenuse}}{\text {base}}$

And,

$\tan \theta=\frac{\text { perpendicular }}{\text { base }}$

where Ө is the angle

Substituting the values

$\left(\frac{\text {hypotenuse}}{\text {base}}\right)^{2}-\left(\frac{\text { perpendicular }}{\text {base}}\right)^{2}$

Solving,

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}$

According to Pythagoras theorem,

$\text { (hypotenuse) }^{2}-\text { (perpendicular) }^{2}=(\text { base })^{2}$

Putting this in the equation;

squared 55 - tan squared 55 =

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}=\frac{(\text {base})^{2}}{(\text {base}) *(\text {base})}=1$

Therefore, sec squared 55 – tan squared 55 = 1

6 0

2 years ago

Find the length of the line segment shown. Round your answer to the nearest tenth.

Marina86 [1]

Answer:

$d=10$

Step-by-step explanation:

Distance Formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step 1: Define endpoint coordinates

(2, 5)

(-6, -1)

Step 2: Substitute and Evaluate

$d=\sqrt{(-6-2)^2+(-1-5)^2}$

$d=\sqrt{(-8)^2+(-6)^2}$

$d=\sqrt{64+36}$

$d=\sqrt{100}$

$d=10$

8 0

2 years ago

What is the sum of the matrices below ?

Vanyuwa [196]

Answer:

$\left[\begin{array}{ccc}4&19&-5\\7&0&-14\end{array}\right] + \left[\begin{array}{ccc}-8&7&0\\-1&17&6\end{array}\right] = \left[\begin{array}{ccc}-4&26&-5\\6&17&-8\end{array}\right]$

Step-by-step explanation:

To add two matrices you just need to add the corresponding entries together. In this case, we have that:

$\left[\begin{array}{ccc}4&19&-5\\7&0&-14\end{array}\right] + \left[\begin{array}{ccc}-8&7&0\\-1&17&6\end{array}\right]=\left[\begin{array}{ccc}4-8&19+7&-5 + 0\\7-1&0+17&-14+6\end{array}\right] = \left[\begin{array}{ccc}-4&26&-5\\6&17&-8\end{array}\right]$

Then, we conclude that the sume of the two matrices is:

$\left[\begin{array}{ccc}4&19&-5\\7&0&-14\end{array}\right] + \left[\begin{array}{ccc}-8&7&0\\-1&17&6\end{array}\right] = \left[\begin{array}{ccc}-4&26&-5\\6&17&-8\end{array}\right]$

3 0

2 years ago

Read 2 more answers

Solve for x: 8x-2x-16=20

Morgarella [4.7K]

Answer:X=6

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

8x−2x−16=20

8x+−2x+−16=20

(8x+−2x)+(−16)=20(Combine Like Terms)

6x+−16=20

6x−16=20

Step 2: Add 16 to both sides.

6x−16+16=20+16

6x=36

Step 3: Divide both sides by 6.

x=6

3 0

2 years ago

Read 2 more answers