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Karo-lina-s [1.5K]
3 years ago
12

A client with tongue occlusion has loss of gag reflex and alterations in level of consciousness. The blood gas test shows oxygen

saturation as 40mm Hg and carbon dioxide saturation as 75 mm Hg. Which type of support provides immediate relief to the client?
Chemistry
1 answer:
siniylev [52]3 years ago
7 0

Answer:

answer is given below

Explanation:

Upper airway obstruction with tongue closure may be associated with damage Changes in alertness and level of consciousness. Clients with severe hypoxia (O2)

Saturation of 40 mm Hg and this is an emergency for hypercapnic (CO2 saturation of 75 mm Hg)

Tracheotomy for relief in 2 minutes. Laryngeal repair is performed to prevent laryngeal.  

Cover cartilage cover. Clears the upper airway obstruction due to abdominal thrust maneuvering  Foreign body. Autoradiating positive airway pressure resets full pressure during breathing

Users with severe sleep apnea

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_KOH + _H₂PO4 → _K₂PO4 + _H₂O​
Hunter-Best [27]

Answer:

2KOH+H2PO4--K2PO4+4H2O

3 0
3 years ago
A 45ml of a 4M solution of CaBr2 contains how many grams of CaBr2?
natta225 [31]

The required mass of calcium bromide is 35.98 grams.

<h3>What is molarity?</h3>

Molarity is any solution is define as the number of moles of solute present in per liter of solution as;

M = n/V, where

  • M = molarity = 4M
  • V = volume = 45mL = 0.045L

Moles will be calculated by using the above equation as:

n = (4)(0.045) = 0.18 mole

Relation between the mass and moles of any substance will be represented as:

n = W/M, where

  • W = given mass
  • M = molar mass

Mass of CaBr₂ = (0.18mol)(199.89g/mol) = 35.98g

Hence required mass of CaBr₂ is 35.98 grams.

To know more about molarity, visit the below link:
brainly.com/question/22283918

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6 0
2 years ago
A 30.7 g sample of Strontium nitrate, Sr(NO3)2•nH2O, is heated to a constant mass of 22.9 g. Calculate the hydration number.
Elodia [21]

Answer:

  • <em>Hydration number:</em> 4

Explanation:

<u>1) Mass of water in the hydrated compound</u>

Mass of water = Mass of the hydrated sample - mass of the dehydrated compound

Mass of water = 30.7 g - 22.9 g = 7.8 g

<u>2) Number of moles of water</u>

  • Number of moles = mass in grams / molar mass

  • molar mass of H₂O = 2×1.008 g/mol + 15.999 g*mol = 18.015 g/mol

  • Number of moles of H₂O = 7.9 g / 18.015 g/mol = 0.439 mol

<u>3) Number of moles of Strontium nitrate dehydrated, Sr (NO₃)₂</u>

  • The mass of strontium nitrate dehydrated is the constant mass obtained after heating = 22.9 g

  • Molar mass of Sr (NO₃)₂ :  211.63 g/mol (you can obtain it from a internet or calculate using the atomic masses of each element from a periodic table).

  • Number of moles of Sr (NO₃)₂ = 22.9 g / 211.63 g/mol =  0.108 mol

<u>4) Ratio</u>

  • 0.439 mol H₂O / 0.108 mol Sr(NO₃)₂ ≈  4 mol H₂O : 1 mol Sr (NO₃)₂

Which means that the hydration number is 4.

4 0
3 years ago
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Use the solubility rules from the Lab 4 introduction and your knowledge of qualitative separation schemes from the lab to answer
cluponka [151]

Answer:

a13+a13

Explanation:

4 0
2 years ago
A solution of which of the following coordination compounds will form a precipitate when treated with aqueous AgNO3?
lidiya [134]

Answer:

[Cr(NH3)6.]C13

Explanation:

Alfred Werner's coordination theory (1893) recognized two kinds of valency;

Primary valency which are nondirectional and secondary valency which are directional.

Hence, the number of counter ions precipitated from a complex depends on the primary valency of the central metal ion in the complex.

We must note that it is only these counter ions that occur outside the coordination sphere that can be precipitated by AgNO3.

If we consider the options carefully, only [Cr(NH3)6.]C13 possess counter ions outside the coordination sphere which can be precipitated when treated with aqueous AgNO3.

3 0
2 years ago
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