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Karo-lina-s [1.5K]
4 years ago
12

A client with tongue occlusion has loss of gag reflex and alterations in level of consciousness. The blood gas test shows oxygen

saturation as 40mm Hg and carbon dioxide saturation as 75 mm Hg. Which type of support provides immediate relief to the client?
Chemistry
1 answer:
siniylev [52]4 years ago
7 0

Answer:

answer is given below

Explanation:

Upper airway obstruction with tongue closure may be associated with damage Changes in alertness and level of consciousness. Clients with severe hypoxia (O2)

Saturation of 40 mm Hg and this is an emergency for hypercapnic (CO2 saturation of 75 mm Hg)

Tracheotomy for relief in 2 minutes. Laryngeal repair is performed to prevent laryngeal.  

Cover cartilage cover. Clears the upper airway obstruction due to abdominal thrust maneuvering  Foreign body. Autoradiating positive airway pressure resets full pressure during breathing

Users with severe sleep apnea

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sergeinik [125]
Rigid crust perhaps
7 0
3 years ago
How much heat, in joules and in calories, must be added to a 75.0–g iron block with a specific heat of 0.449 j/g °c to increas
lianna [129]

Answer:

Q=50,849.25J\\\\Q=12,153.3cal

Explanation:

Hello!

In this case, given the mass, temperature change and specific heat, it is possible to compute the required heat in joules as shown below:

Q=mC(T_2-T_1)\\\\Q=75.0g*0.449\frac{J}{g\°C}(1535\°C-25\°C)\\\\Q=50,849.25J

Now, since 1 cal =4.184 J, this result in calories is:

Q=50,849.25J*\frac{1cal}{4.184J}\\\\Q=12,153.3cal

Best regards!

7 0
3 years ago
What is the mass defect of lithium? Assume the following:
Bumek [7]

Answer:

Δm = 3.0684

Explanation:

Data Given:

Atomic number of lithium = 3

Atomic mass of lithium = 7.0144 amu

Mass of 1 proton = 1.0073 amu

Mass of 1 neutron = 1.0087 amu

Solution:

Mass Defect:

Mass defect is the difference of mass number of an atom and its atomic number.

Formula used

Δm = [Z (mass of proton + mass of nutron)  + ( A − Z ) mass of nutron] − m of atom

where:

Δm = mass defect (amu)

Z = atomic number

A = mass number

Put values in formula

Δm = [3 ( 1.0073 amu + 1.0087 amu)  + ( 7 − 3 ) 1.0087 ] − 7.0144

Δm = [3 (2.016)  + (4) 1.0087 ] − 7.0144

Δm = [(6.048)  + (4.0348) ] − 7.0144

Δm = 10.0828 − 7.0144

Δm = 3.0684

7 0
3 years ago
Part A
KonstantinChe [14]

Answer:

The answer to your question is below

Explanation:

A.

[H₃O⁺] = 2 x 10⁻¹⁴ M

pH = ?

Formula

                                    pH = - log [H₃O⁺]

Substitution

                                    pH = - log [2 x 10⁻¹⁴]

Result

                                    pH = 13.7          

B.

[H₃O⁺] = ?

pH = 3.12

Formula

                                   pH = - log [H₃O⁺]

Substitution

                                   3.12 = - log [H₃O⁺]

                                   10^{-3.12} = [H_{3} O^{+}]

Result

                                  [H₃O⁺] = 7.59 M

   

7 0
3 years ago
a piece of metal is heated to 100℃ and placed into 75.0g of water in a coffee-cup calorimeter. Initially, the temperature of the
Jet001 [13]

Answer:

The mass of this piece of metal is 37.68g

Explanation:

<u>Step 1:</u> Given data

q = m*ΔT *Cp

⇒with m = mass of the substance

⇒with ΔT = change in temp = final temperature T2 - initial temperature T1

⇒with Cp = specific heat (Cpwater = 4.184J/g °C) (Cpmetam = 0.9J/ g °C)

<u>Step2 : </u>

For this situation : we get for q = m*ΔT *Cp

q(lost, metal) = q(gained, water)

- mass of metal(ΔT)(Cpmetal) = mass of water (ΔT) (Cpwater)

-m (30.6 -100) * 0.9 = 75g *( 30.6 - 23.1) * 4.184J / g °C

-m * (-69.4) * 0.9 = 75g * (7.5) * 4.184J / g °C

-m * (-69.4) *0.9 = 2353.5

-m = 2353.5 / (-69.4 *0.9) = -37.68

m = 37.68g

The mass of this piece of metal is 37.68g

4 0
3 years ago
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