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Karo-lina-s [1.5K]
3 years ago
12

A client with tongue occlusion has loss of gag reflex and alterations in level of consciousness. The blood gas test shows oxygen

saturation as 40mm Hg and carbon dioxide saturation as 75 mm Hg. Which type of support provides immediate relief to the client?
Chemistry
1 answer:
siniylev [52]3 years ago
7 0

Answer:

answer is given below

Explanation:

Upper airway obstruction with tongue closure may be associated with damage Changes in alertness and level of consciousness. Clients with severe hypoxia (O2)

Saturation of 40 mm Hg and this is an emergency for hypercapnic (CO2 saturation of 75 mm Hg)

Tracheotomy for relief in 2 minutes. Laryngeal repair is performed to prevent laryngeal.  

Cover cartilage cover. Clears the upper airway obstruction due to abdominal thrust maneuvering  Foreign body. Autoradiating positive airway pressure resets full pressure during breathing

Users with severe sleep apnea

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<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of magnesium nitrate and aqueous ammonia (ammonium hydroxide) is given as:

Mg(NO_3)_2(aq.)+2NH_4OH(aq.)\rightarrow Mg(OH)_2(s)+2NH_4NO_3(aq.)

A white precipitate of magnesium hydroxide is formed in the above reaction.

Ionic form of the above equation follows:

Mg^{2+}(aq.)+2NO_3^-(aq.)+2NH_4^+(aq.)+2OH^-(aq.)\rightarrow Mg(OH)_2(s)+2NH_4^+(aq.)+2NO_3^-(aq.)

As, ammonium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

Mg^{2+}(aq.)+2OH^-(aq.)\rightarrow Mg(OH)_2(s)

Hence, the net ionic equation is written above.

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<u>Answer:</u> The correct answer is Option b.

<u>Explanation:</u>

To calculate the amount of heat absorbed or released, we use the following equation:

q=mc\Delta T    .....(1)

where, q = amount of heat absorbed or released.

m = mass of the substance

c = heat capacity of  water = 4.186 J/g ° C      

\Delta T = Change in temperature

  • <u>For Trial 1:</u>

We are given:

m=30g\\\Delta T=[40-0]^oC=40^oC\\q=?J

Putting values in equation 1, we get:

q=30g\times 4.186J/g^oC\times 40^oC

q = 5023.2 J

  • <u>For trial 2:</u>

We are given:

m=40g\\\Delta T=[40-30]^oC=10^oC\\q=?J

Putting values in equation 1, we get:

q=40g\times 4.186J/g^oC\times 10^oC

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Heat gained by Trial 1 than trial 2 = (5023.2-1674.4)J=3347J

Hence, the amount of heat gained in Trial 1 about 3347 J more than the heat released in Trial 2.

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