Which type of radiation particle cannot be completely blocked by lead shielding

4vir4ik [10]

Matter is anything that has mass and occupies space, It can exist in 3 states, or phases: solid, liquid, and gas.

Solid molecules are closely packed together and retain a fixed shape.

Liquid molecules aren't packed very closely, and take the shape of the bottom of the container.

Gas molecules are far apart and fill the container

completely.

7 0

2 years ago

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Consider 100.0 g samples of two different compounds consisting only of carbon and oxygen. One compound contains 27.2 g of carbon

Pani-rosa [81]

Answer: The ratio of carbon in both the compounds is 1 : 2

Explanation:

Law of multiple proportions states that when two elements combine to form two or more compounds in more than one proportion. The mass of one element that combine with a given mass of the other element are present in the ratios of small whole number. For Example: $Cu_2O\text{ and }CuO$

For Sample 1:

Total mass of sample = 100 g

Mass of carbon = 27.2 g

Mass of oxygen = (100 - 27.7) = 72.8 g

To formulate the formula of the compound, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{27.2g}{12g/mole}=2.26moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{72.8g}{16g/mole}=4.55moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 2.26 moles.

For Carbon = $\frac{2.26}{2.26}=1$

For Oxygen = $\frac{4.55}{2.26}=2.01\approx 2$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : O = 1 : 2

Hence, the formula for sample 1 is $CO_2$

For Sample 2:

Total mass of sample = 100 g

Mass of carbon = 42.9 g

Mass of oxygen = (100 - 42.9) = 57.1 g

To formulate the formula of the compound, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{42.9g}{12g/mole}=3.57moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{57.1g}{16g/mole}=3.57moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.57 moles.

For Carbon = $\frac{3.57}{3.57}=1$

For Oxygen = $\frac{3.57}{3.57}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : O = 1 : 1

Hence, the formula for sample 1 is $CO$

In the given samples, we need to fix the ratio of oxygen atoms.

So, in sample one, the atom ratio of oxygen and carbon is 2 : 1.

Thus, for 1 atom of oxygen, the atoms of carbon required will be = $\frac{1}{2}\times 1=\frac{1}{2}$

Now, taking the ratio of carbon atoms in both the samples, we get:

$C_1:C_2=\frac{1}{2}:1=1:2$

Hence, the ratio of carbon in both the compounds is 1 : 2

8 0

2 years ago

12. If a solution has a pH of 3, what would the pOH value of that solution be? *

butalik [34]

Answer:

The correct answer is pOH= 11

Explanation:

From the aqueous acid-base equilibrium we know that

pH + pOH = 14

If we know pH, we can calculate pOH as follows:

pOH = 14 - pH

In this problem, the solution has a pH of 3, so:

pOH = 14 - 3 = 11

8 0

2 years ago

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WILL MARK BRAINLIST

Free_Kalibri [48]

Answer:

The average speed must be 30mph so this means the car traveled for 2hrs 60/30

7 0

2 years ago

Justin mixed two clear liquids together during an experiment and made the following observations: The mixed liquids decreased in

kvasek [131]

Answer:

B

Explanation:

A chemical change occurred, and this caused the liquid’s physical properties to change.

when we read her experiment we can see that color changed to blue, it is because new products are formed. And the temperature cause this.

5 0

2 years ago

Which type of radiation particle cannot be completely blocked by lead shielding ​

Which type of radiation particle cannot be completely blocked by lead shielding