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zimovet [89]
3 years ago
15

Which type of radiation particle cannot be completely blocked by lead shielding ​

Chemistry
1 answer:
Katen [24]3 years ago
5 0

Answer:

gamma rays

Explanation:

You might be interested in
2. Sate the method of collecting gases that are<br>ii). Lighter than ai<br>i). denser than air​
dybincka [34]

Answer:

i) Upwards delivery

ii) Downwards delivery

Explanation:

The methods used in the collection of gases are quite different depending on the state of the gas. The solubility and density of gases are the factors that determine the method of collection to be used.

Upwards delivery is used to collect gases that are soluble in water and lighter compared to air. Examples of these kind of gases include; Cl2 and SO2

Downwards delivery is used to collect gases that are soluble in water and denser than air. An example of this kind of gas is ammonia gas, NH4.

3 0
3 years ago
If a body`s efficiency is 75% what does it mean?​
snow_tiger [21]

Answer: It’s producing 75% of it’s potential.

Example: If I were to be playing basketbal, and my body was working at 75%, then there is 25% of energy that I’m not using, making me worse than if I was using 100%.

6 0
3 years ago
R equals The formula for Ohm's law can be written: R equals _____. I / V V / I I x V
Licemer1 [7]

Answer:

R = V / I

Explanation:

Ohm's Law:

V = I * R , V = voltage , I = current , R = resistance

rearranging to solve R,

R = V / I

4 0
3 years ago
If 4.00 g of NaCl react with 10.00 g of AgNO3, what is the excess reactant?
Mekhanik [1.2K]
The reaction formula of this is NaCl + AgNO3 = NaNO3 + AgCl. The mole number of NaCl is 4/58.5=0.068 mol. The mole number of AgNO3 is 10/170=0.059 mol. So the NaCl is excess.
7 0
3 years ago
Read 2 more answers
If the density of ethanol, C2H5OH, is 0.789 g/mL. How many milliliters of ethanol are needed to produce 15.0 g of CO2 according
Svetradugi [14.3K]

Answer:

9.94 mL, the volume of ethanol needed

Explanation:

The reaction is:

C₂H₅OH(l) + 3 O₂(g) → 2 CO₂(g) + 3 H₂O(l)

We convert the mass of the formed product to moles:

15 g . 1mol / 44g = 0.341 moles

2 moles of dioxide are produced by 1 mol of ethanol, in order to stoichiometry.

Therefore, 0.341 moles of CO₂ must be produced by (0.341. 1) / 2 = 0.1705 moles of alcohol.

We convert the moles to mass, and then, the mass to volume by the use of density.

0.1705 mol . 46 g / 1 mol = 7.84 g of ethanol

Ethanol density = Ethanol mass /Ethanol volume

Ethanol volume = Ethanol mass /Ethanol density → 7.84 g /0.789 g/mL =

9.94 mL

7 0
3 years ago
Read 2 more answers
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