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Blizzard [7]
3 years ago
11

Here are Xavier's bowling scores:

Mathematics
1 answer:
salantis [7]3 years ago
4 0

Answer:

Lower Quartile = 132

Step-by-step explanation:

Arranging it in ascending Order:

112, 130, 132, 140, 149, 151, 163, 172, 185, 190, 200

Lower quartile = (N+1)^{th} Term \frac{1}{4}

Where N = 11

Lower Quartile = \frac{1}{4} (12)^{th} Term

Lower Quartile = 3rd Term

So,

Lower Quartile = 132

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Determine the common factors and HCF for each of the following terms.
Ahat [919]

Answer: Please see explanation column for answers

Step-by-step explanation:

When a number  divides into another number without a remainder, it s called a factor of that number.  Lets say we want to  find the common factors of two numbers, we get the  factors of each one and  compare them. The common factor is the one that is found in both lists

While The Highest common factor, is the highest factor number found in both lists.

b) 2b , 3b

Factors of 2b= 1, 2 and b

Factors of 3b=1, 3 and b

Common factors =1 and  b

HCF=1b

e) 5bc, 2c2, 3cd

Factors of 5bc=  1, 5, b, c

Factors of 2c2= 1,  2, c, c2

Factors of  3cd= 1, 3, c, d

Common factors = 1 and c

HCF= 1c

f) 4a2b, 8b2c, 6bcd

Factors of 4a2b=  1, 2, 4, a, a2, b

Factors of 8b2c= 1, 2, 4, 8, b, b2, c

Factors of  6bcd= 1, 2,3,6, b, c,d

Common factors = 1, 2 , b

HCF=  2b

3 0
3 years ago
I FREAKING NEED HELPPP!!!
Ratling [72]

Answer:

\boxed{\begin{bmatrix}  3 &  - 1 \\  - 3 & 4\end{bmatrix}  = 12 - 3 =  \boxed{9} }\\ \\  \boxed{\begin{bmatrix}   -12 &  - 1 \\  12 &  5\end{bmatrix}  =  - 60-  ( - 12) =  \boxed{ - 48}} \\  \\ \boxed{\begin{bmatrix}  0&  - 1 \\  17 & 4\end{bmatrix}  = 0 -( - 17 )=  \boxed{17}} \\  \\\boxed{ \begin{bmatrix}  8&  - 1 \\  -  4 &  - 1\end{bmatrix}  =  - 8 - 4 =  \boxed{ - 12} }\\  \\ \boxed{\begin{bmatrix}  2 &  - 1 \\  2 &  - 1\end{bmatrix}  =  - 2 - ( - 2) =  \boxed{0}} \\  \\ \boxed{ \begin{bmatrix}  1 &  0\\  0 &1\end{bmatrix}  = 1 - 0 =  \boxed{1}}

Step-by-step explanation:

the \: determinant \: of  \: a \: matrix : A  \to\\If  \: A  =\begin{bmatrix}  x & y \\ a & b \end{bmatrix} \: then : \\  its \: determinant \: is \: givn \: by \to \\  |A|  =  (b \times x) - (a \times y) \\  \boxed{|A|  = bx - ax}

♨Rage♨

5 0
3 years ago
Suppose that a point (X,Y) us chosen at random from the rectangle S defined as follows: S={(x,y) : 0<= x <=2 and 1<=y&l
mrs_skeptik [129]
For a 19 foot scale find the frequency of a note to the frequency of the preceding note?
7 0
3 years ago
Find the value of 7v-10 given that -11v-7=4. Simplify your answer as much as possible.
densk [106]

First thing to do is solve the given equation for v

-11v-7 = 4

-11v = 4+7

-11v = 11

v = 11/(-11)

v = -1

Once we know this, we can use it to compute the following

7v-10 = 7*(-1) - 10 = -7 - 10 = -17

--------------------------------

Answer: -17

4 0
3 years ago
What would be the angle between the two perpendicular lines.​
Anna007 [38]

Answer:

<em>90 degrees</em>

<em>90 degreesPerpendicular lines are lines that intersect at a <u>right (90 degrees) angle.</u></em>

5 0
3 years ago
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