3 years ago

3x + 4 213 or 2x -15 -11

Mathematics

1 answer:

ehidna [41]3 years ago

6 0

Answer:

743979734

Step-by-step explanation:

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Lisa says that 43 is a 2 digit odd number that is composite. Is she correct? Explain

jolli1 [7]

No she is not correct as 43 is a prime number. It is an odd number though.

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3 years ago

Find the sum. Express your answer in simplest form. 9a^2-5/b^2+2 + -2a^2+4/b^2+2

KonstantinChe [14]

Answer:

Step-by-step explanation:

$\frac{9a^{2}-5}{b^{2}+2}+\frac{-2a^{2}+4}{b^{2}+2}=\frac{9a^{2}-5-2a^{2}+4}{b^{2}+2}\\\\=\frac{9a^{2}-2a^{2}-5+2}{b^{2}+2}\\\\=\frac{7a^{2}-3}{b^{2}+2}$

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3 years ago

Can someone answer these!

vitfil [10]

4×2=8

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3 years ago

One weekend Ella sells a total of 52 prints for a total of $2,975.Small prints cost $50 and large prints cost $75. How many of e

xz_007 [3.2K]

Answer:

ella sold 37 small prints and 15 large prints.

Step-by-step explanation:

37×50=1850

15×75=1125

1850+1125=2975

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3 years ago

Use a surface integral to find the general formula for the surface area of a cone with height latex: h and base radius latex: a(

BlackZzzverrR [31]

We can parameterize this part of a cone by

$\mathbf s(u,v)=\left\langle u\cos v,u\sin v,\dfrac hau\right\rangle$

with $0\le u\le a$ and $0\le v\le2\pi$ . Then

$\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|\,\mathrm du\,\mathrm dv=\sqrt{1+\dfrac{h^2}{a^2}}u\,\mathrm du\,\mathrm dv$

The area of this surface (call it $\mathcal S$ ) is then

$\displaystyle\iint_{\mathcal S}\mathrm dS=\sqrt{1+\frac{h^2}{a^2}}\int_{v=0}^{v=2\pi}\int_{u=0}^{u=a}u\,\mathrm du\,\mathrm dv=a^2\sqrt{1+\frac{h^2}{a^2}}\pi=a\sqrt{a^2+h^2}\pi$

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3 years ago